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EleoNora [17]
3 years ago
6

Please help I don't know how to do this

Physics
2 answers:
NeX [460]3 years ago
7 0
The answer to your question is C
alex41 [277]3 years ago
6 0
Solubility is how much solute will dissolve in solvent. 
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The radius of the earth very nearly circular orbit around the sun is
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Answer

given,

radius of earth,r = 1.5 x 10¹¹ m

Time,T = 365 days

         = 365 x 24 x 3600 s  

earth velocity,

v=\dfrac{2\pi r}{T}

v=\dfrac{2\pi (1.5\times 10^{11})}{365\times 24\times 3600}

    v = 3 x 10⁴ m/s

centripetal acceleration of the earth

 a = \dfrac{v^2}{r}

 a = \dfrac{(3\times 10^4)^2}{1.5\times 10^{11}}

        a = 6 x 10⁻³ m/s²

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A line that describes volume across the surface of an object or shape is called a ____ line.
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4 years ago
First consider a Carnot engine that operates between a hot reservoir at 58°C and a cold reservoir at -17°C. In running 24 minute
jok3333 [9.3K]

Answer:

Explanation:

Given that,

Hot reservoir temperature is

TH = 58°C

TH = 58 + 273 = 331 K

Cold reservoir temperature

TC = -17°C

TC = -17°C + 273 = 256K

In 24minutes 590 J of heat was removed from hot reservoir

t = 24mins

t = 24 × 60 = 1440 seconds

Then,

Power is given as

P = E / t

P = 590 / 1440

P = 0.41 W

Since this removed from the hot reservoir, then, QH = 0.41W

We want to find heat expelled to the cold reservoir QX

Efficiency is given as

η = 1 - TH/TC = 1 - QH/QC

1 - TH/TC = 1 - QH/QC

TH/TC = QH/QC

Make QC subject of formula

QC = QH × TC / TH

QC = 0.41 × 256 / 331

QC = 0.317 W

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3 years ago
A space capsule having a mass of 9.0×10^2 kg is projected vertically upwards from the Earth’s surface with an initial kinetic en
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sg

Explanation:

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