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Elina [12.6K]
2 years ago
12

The velocity of a body is given by the equation v= a + bx, where 'x' is displacement. The unit of b is .......

Physics
1 answer:
valina [46]2 years ago
8 0

Answer:

s^ -1    ( or    1/sec)

Explanation:

Velocity is given in units of displacement / sec

like feet /sec   or   m/sec    

so b would have units of   s^-1

(or perhaps a more general term would be   time^-1)

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Evgen [1.6K]

Answer:

mass

.

Explanation:

5 0
3 years ago
Which of these statements best explains why trees in a forest do not grow very close to one another?
SpyIntel [72]
Answer: trees compete for resources directly around them . 
7 0
3 years ago
Read 2 more answers
The solid metallic sphere is replaced with a hollow insulating shell of radius a. A charge Q is spread uniformly over the hollow
Annette [7]

Answer:

Zero

Explanation:

It is given that the charge is uniformly spread at the surface of hollow spherical shells.

There is no charge with in the hollo shell. hence, with zero charge the  electric field intensity is also zero.

Thus,

Magnitude of the electric field strength inside the hollow shell at r is zero

5 0
3 years ago
In uniform circular motion, how does the acceleration change when the speed is increased by a factor of 3? When the radius is de
crimeas [40]

Answer:

The acceleration will become 9/2 times.

a' =9/2 a

Explanation:

We know that acceleration of a particle when it is moving in the circular path is given as

a=\omega^2\ r

r=radius

ω= angular speed

If the speed ω '= 3 ω

If the radius ,r'=\dfrac{r}{2}

The final acceleration =a'

a'=\omega^2'\ r'

a'=(3\omega)^2\times \dfrac{r}{2}

a'=9\omega^2\times \dfrac{r}{2}

a'=\omega^2\times \dfrac{9r}{2}

a'= \dfrac{9r}{2}\times \omega^2\times r

a'=\dfrac{9}{2}a

Therefore the acceleration will become 9/2 times.

5 0
3 years ago
Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from west to east,
pychu [463]

Answer:

(i) Relative velocity of B w.r.t A= Sum of speeds of trains

=54+90

=144kmph

(ii)Relative velocity of B w.r.t Ground(G)=v

B/G

=−90kmph

v

G

=0

Relative velocity of ground(G) w.r.t B =v

G/B

=v

G

−v

B/G

v

G/B

=0−(−90)

v

G/B

=90kmph

4 0
3 years ago
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