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3 years ago

Complete the factorization of 4x^2 - 9

Mathematics

1 answer:

Vaselesa [24]3 years ago

5 0

Answer:

$4 {x}^{2} - 9 \\ {2}^{2} {x}^{2} - {3}^{2} \\ = (2x - 3)(2x + 3)$

hope this helps you....

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What is 3/12 equivalent to ?/100

enyata [817]

Answer:

25/100

Step-by-step explanation:

3/12 can be simplified to 1/4

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2 years ago

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

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3 years ago

You are walking along a path y= 2x + 12 and your

UNO [17]

Answer:

(-1,10)

Step-by-step explanation:

At the point when the paths cross, the respective x and y values of each equation will be equal.

Your path is y=2x+12, and your friends path is 4x+y=6. Sub 2x+12 in for y (from your path's equation) into your friends equation to find the value of x:

4x+2x+12=6

6x=-6

x=-1

y=2x+12

y=2(-1)+12=10

So you will cross paths at (-1,10)

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3 years ago

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0992929jaoKakoxoxoxosos

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2 years ago

Prime factor tree of 385

timama [110]

11*5*7

385 breaks down to 7 and 55. Bring the seven down. Break 55 down to 11 and 5. Then bring those down and you get 11*5*7

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3 years ago