4x + 1 = 3x + 5 what’s the answer?

Yuri purchased 8 trees to have planted at his house. The store charged a delivery fee of $5 per tree.

cestrela7 [59]

Answer:

$16.

Step-by-step explanation:

Let t represent the cost of each tree.

We have been given that Yuri purchased 8 trees to have planted at his house. So the cost of 8 trees will be 8t.

We are also told that the store charged a delivery fee of $5 per tree. So the delivery charges of 8 trees will be $8\times \$5=\$40$

The total cost of purchasing 8 trees will be $8t+40$ .

Since the total cost of the trees including the delivery was $168, so we can get an equation as:

$8t+40=168$

$8t+40-40=168-40$

$8t=128$

Upon dividing both sides of our given equation by 8, we will get:

$\frac{8t}{8}=\frac{128}{8}$

$t=16$

Therefore, the cost of each tree is $16.

5 0

3 years ago

14)If you multiply John's age by 4 and then

natulia [17]

Answer:

there was alot of math here but i got 10

Step-by-step explanation:

so first u add 10 and 2 u get 12 then u multiply 4 then u get 48 and divide that by 4 and then subtract 2 and get 10. hope this helped

6 0

3 years ago

Does 7x+3x-8 = 2(5x-4) have one solution, no solution, or infinitely many solutions?

USPshnik [31]

Answer: only has one solution

Step-by-step explanation: If you find the answer for 7x+3x-8, youll get 10x+8. This will be the same answer for 2(5x-4). Making them equal and having only one solution

5 0

3 years ago

Read 2 more answers

Each year a certain type of tree grows vertically 14/15 as much as it did the year before. If the tree grows 1.5m during the fir

Anastaziya [24]

https://answers.yahoo.com/question/index?qid=20180411132938AApZYZz

8 0

3 years ago

A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec

Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (n ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

$Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18$

The sample size is, n = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

$\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191$

(a)

The null hypothesis is:

H₀: The usual load is 13 credits, i.e. μ = 13.

Assume that the significance level of the test is, α = 0.05.

Construct a (1 - α) % confidence interval for population mean to check the claim.

The (1 - α) % confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\times SE$

For 5% level of significance the two tailed critical value of z is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct the 95% confidence interval as follows:

$CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)$

As the null value, μ = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

$P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z$

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0

3 years ago

Read 2 more answers