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Dafna1 [17]
3 years ago
6

Which of the following statements best describes an electromagnetic wave with a short wavelength?

Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0
It’s probably d or b
nikitadnepr [17]3 years ago
5 0

Answer:b

Explanation:

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A newly discovered planet has the same mass as the Earth, but a person standing on the surface of the planet experiences a force
Dafna11 [192]

This question deals with the acceleration due to gravity on the surface of the planet. The value of the acceleration due to gravity on the surface of two planets, that is Earth and on the surface of another planet are compared to find out the relation between the radii of both planets, provided their masses are the same.

The correct option for the radius of the new planet is "Option 3: Square Root of 3 R"

The value of the acceleration due to gravity on the surface of a planet is given by the following formula:

g = \frac{GM}{R^2}----------- eqn(1)

where,

g = acceleration due to gravity on Earth

G = Universal Gravitational Constant

M = mass of the Earth

R = Radius of the Earth

Now, the same formula for the acceleration due to gravity on the surface of the other planet can be written as follows:

g' = \frac{GM'}{R'}\\\\------------- eqn(2)

where,

g' = acceleration due to gravity on the new planet

G = Universal Gravitational Constant

M' = mass of the new planet

R' = Radius of the new planet

According to the given condition, the new planet has the same mass as the Earth's mass but the acceleration due to gravity on the surface of the new planet is one-third of the acceleration due to gravity on the surface of Earth.

M'=M\\\\g'=\frac{1}{3}g

using eqn (1) and eqn (2):

\frac{GM}{R'^2}=\frac{1}{3}\frac{GM}{R^2}\\\\R'^2=3R^2\\\\R' = \sqrt{3}R

Hence, the radius of the new planet is found to be equal to the square root of 3 times the radius of the Earth (Square Root of 3 R).

Learn more about acceleration due to gravity on the surface of a planet here:

brainly.com/question/15575318?referrer=searchResults

brainly.com/question/19552330?referrer=searchResults

7 0
3 years ago
If the same pressure is exerted over a greater area will more of less force result? Group of answer choices :
Zigmanuir [339]

Answer:

More force

Explanation:

Pressure and force are related by the equation:

p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area

We can re-arrange the equation as

F=pA

In this problem, the pressure is kept the same (p' = p) while the area is increased. As we can see from the previous equation, the force applied is directly proportional to the area: therefore, a greater area means also a greater force.

8 0
4 years ago
What is the least value of an ammeter <br>Is it 1. 0.1<br>2. 0.10<br>3. 0.2<br>4. 0.5​
givi [52]

The least value varies depends on ammeter range. In the given question, ammeter range is not mentioned. So, the least value of an ammeter is 0.1 or 0.5 (depends on ammeter range).

<u>Explanation:</u>

The least value of an ammeter is the measure of the smallest number which can be observed in ammeter. So the least value will be varying depending upon its range. If we consider the range of ammeter is 30 A and the scale readings are 10 numbers, then the least value will be 30/10 = 3 A per scale.

So the least value is determined as \frac{Range of ammeter}{No.of scales}

So among the given options 0.1 is most suitable for an ammeter with range of 3 A with 30 divisions.

3 0
3 years ago
A large crate is at rest on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.500. A f
Nookie1986 [14]

Answer:

93.4 kg

Explanation:

Draw a free body diagram.  There are three four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

Applied force F pulling up and to the right, 30.0° above the horizontal.

Sum of forces in the y direction:

∑F = ma

N + F sin 30.0° − mg = 0

N = mg − ½ F

Sum of forces in the x direction:

∑F = ma

F cos 30.0° − Nμ = 0

½√3 F = Nμ

Substitute:

½√3 F = (mg − ½ F) μ

½√3 F / μ = mg − ½ F

½√3 F / μ + ½ F = mg

½F (√3 / μ + 1) = mg

m = F (√3 / μ + 1) / (2g)

Plug in values:

m = 410 N (√3 / 0.500 + 1) / (2 × 9.8 m/s²)

m = 93.4 kg

4 0
3 years ago
Read 2 more answers
11. A ball is thrown up and attains maximum height of 20 m. Calculate its initial speed. (g = 10 ms')
Archy [21]

final velocity = 0

acceleration = - 10 m/ s 2

distance. = 20 m

u = ?

v^2 - u ^2 = 2 a s

0^2 - u^ 2 = 2 * -10 * 20

-u^2 = -400

u = √ 400

u = 20m / s

5 0
3 years ago
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