Answer:
It will never pass, because things fall at the same time, if there are no outside fource or other different like shape, gravity…
Answer: If one billiard ball hits another, the second will move with the same force as the first.
A child wants to jump to climb a tree (reaction), he must push the ground to propel himself (action).
A man deflates a balloon; the force with which the air comes out causes the balloon to move from one side to the other.
Explanation:
Answer:
A.) 4 revolution
B.) 0.2 revolution
C.) 4 seconds
D.) 2.75 m/s
Explanation:
Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m
Solution
1 revolution = 2πr
Where r = 1.75m
A. How many revolutions will it make in 3 minutes?
(2π × 1.75) / 3
10.9955 / 3
3.665 RPM
Number of revolution = 15 / 3.665
Number of revolution = 4 revolution
B. How many revolutions will it make in 10.0 seconds?
First convert 10 seconds to minutes
10/60 = 0.167 minute
(2π × 1.75) / 0.167
10.9955 / 0.167
65.973
Number of revolution = 15 / 65.973
Number of revolution = 0.2 revolution
C. How long does it take for a person to make 1 complete revolution?
15 = 1 / t
Make t the subject of formula
t = 1/15
t = 0.0667 minute
t = 4 seconds
D. What is the velocity in m/s of person standing on its edge?
Velocity in m/ s will be:
Velocity = (15 × 2pi × r) / 60
Velocity = 164.9334 / 60
Velocity = 2.75 m/s
In light of this, V=V 0 loge (r/r 0 ) Field E= dr dV =V 0(r0r) eE= r mV2 alternatively, reV0r0=rmV2. V=(m eV 0 r 0 ) \ s1 / 2mV=(m e V 0 r 0 ) 1/2 = constant mvr= 2 nh, also known as Bohr's quantum condition or Hermitian matrix.
Show that the eigenfunctions for the Hermitian matrix in review exercise 3a can be normalized and that they are orthogonal.
Demonstrate how the pair of degenerate eigenvalues for the Hermitian matrix in review exercise 3b can be made to have orthonormal eigenfunctions.
Under the given Hermitian matrix, "border conditions," solve the following second order linear differential equation: d2x/ dt2 + k2x(t) = 0 where x(t=0) = L and dx(t=0)/ dt = 0.
To know more about Hermitian click on the link:
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Explanation:
Red, green, and blue are therefore called additive primaries of light. ... When you block two lights, you see a shadow of the third color—for example, block the red and green lights and you get a blue shadow. If you block only one of the lights, you get a shadow whose color is a mixture of the other two.
First, your definition of a shadow is incorrect. A shadow is an area that receives less light than its surroundings because a specific source of light is blocked by whatever is "casting" the shadow. Your example of being outside reveals this. The sky and everything around you in the environment (unless you are surrounded by pitch black buildings) is sending more than enough light into your shadow, to reveal the pen to your eyes. The sky itself diffuses the sunlight everywhere, and the clouds reflect plenty of light when they are not directly in front of the Sun.
If you are indoors and have two light bulbs, you can throw two shadows at the same time, possibly of different darknesses, depending on the brightness of the light bulbs.
It can take a lot of work to get a room pitch black. One little hole or crack in some heavy window curtains can be enough to illuminate the room. There are very few perfectly dark shadows.