Answer:a) 34.5 N; b) 24.5 N; c) 10 N; d) 1J
Explanation: In order to solve this problem we have to used the second Newton law given by:
∑F= m*a
F-f=m*a where f is the friction force (uk*Normal), from this we have
F= m*a+f=5 Kg*2 m/s^2+0.5*5Kg*9.8 m/s^2= 34.5 N
then f=uk*N=0.5*5Kg*9.8 m/s^2= 24.5N
the net Force = (34.5-24.5)N= 10 N
Finally the work done by the net force is equal to kinetic energy change so
W=∫Force net*dr= 10 N* 0.1 m= 1J
You can find the magnitude of the resultant vector : (B). By adding the magnitudes of the two vectors
<h3>Meaning of Vectors</h3>
A vector can be defined as any quantity which possesses magnitude and also has direction.
A Vector quantity is very useful because This type of quantity gives more details to the student or teacher analyzing it.
Lear more about Vectors: brainly.com/question/25705666
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According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/

.
Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/

= 13.8 N
Hope this helps!
It's not in motion when the line straight and flat . there's #9