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Dmitrij [34]
3 years ago
11

200 grams of an organic sample which contains only carbon, hydrogen, and oxygen is analyzed and found to contain 97.30 grams of

carbon, 16.22 grams of hydrogen and the remainder oxygen. What is the empirical formula for the compound?

Chemistry
2 answers:
faltersainse [42]3 years ago
4 0

Answer:

The Empirical formula of an organic compound is=C_3H_6O_2

Explanation:

Mass of an organic compound = 200 g

Mass of carbon = 97.30 g

moles of carbon = \frac{97.30 g}{12 g/mol}=8.108 mol

Mass of hydrogen = 16.22 g

Moles of hydrogen = \frac{16.22 g}{1 g/mol}=16.220 mol

Mass of oxygen = 200 g - 97.30 g - 16.22 g = 86.48 g

Moles of oxygen =\frac{86.48 g}{16 g/mol}=5.405 mol

Divide the all the moles of element with smallest value of moles.

Carbon = \frac{8.108 mol}{5.405 mol}=1.5

Hydrogen = \frac{16.220 mol}{5.405 mol}=3

Oxygen =\frac{5.405 mol}{5.405 mol}=1

Empirical formula =C_{1.5}H_3O_1

Converting them into whole number ratios.

Empirical formula =C_3H_6O_2

ipn [44]3 years ago
3 0
The empirical formula for 200 grams of an organic sample which contains carbon,hydrogen, and oxygen is C3H6O

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Explanation:

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mash [69]

Answer:

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Explanation:

8 0
3 years ago
Which of the following list all the elements that are present in a molecule of potassium carbonate K2C03?
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H
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3 0
3 years ago
55 L of a gas at 25oC has its temperature increased to 35oC. What is its new volume?
ladessa [460]

Answer:

Approximately 56.8 liters.

Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.

Explanation:

Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1},

where

  • V_2 is the final volume,
  • V_1 is the initial volume,
  • T_2 is the final temperature in degrees Kelvins.
  • T_1 is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

T_1 = \rm 25^{\circ}C = (25 + 273.15)\; K = 298.15\; K.

T_2 = \rm 35^{\circ}C = (35 + 273.15)\; K = 308.15\; K.

Apply Charles's Law to find the new volume of this gas:

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 55\;L \times \frac{308.15\; K}{298.15\; K} = 56.8\; L.

8 0
3 years ago
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