Question

200 grams of an organic sample which contains only carbon, hydrogen, and oxygen is analyzed and found to contain 97.30 grams of carbon, 16.22 grams of hydrogen and the remainder oxygen. What is the empirical formula for the compound?

Answer 1

Answer:

The Empirical formula of an organic compound is=$C_3H_6O_2$

Explanation:

Mass of an organic compound = 200 g

Mass of carbon = 97.30 g

moles of carbon = $\frac{97.30 g}{12 g/mol}=8.108 mol$

Mass of hydrogen = 16.22 g

Moles of hydrogen = $\frac{16.22 g}{1 g/mol}=16.220 mol$

Mass of oxygen = 200 g - 97.30 g - 16.22 g = 86.48 g

Moles of oxygen =$\frac{86.48 g}{16 g/mol}=5.405 mol$

Divide the all the moles of element with smallest value of moles.

Carbon = $\frac{8.108 mol}{5.405 mol}=1.5$

Hydrogen = $\frac{16.220 mol}{5.405 mol}=3$

Oxygen =$\frac{5.405 mol}{5.405 mol}=1$

Empirical formula =$C_{1.5}H_3O_1$

Converting them into whole number ratios.

Empirical formula =$C_3H_6O_2$

Answer 2

The empirical formula for 200 grams of an organic sample which contains carbon,hydrogen, and oxygen is C3H6O