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Archy [21]
3 years ago
12

In a fixed volume, when temperature increases, pressure _______. *

Chemistry
2 answers:
TiliK225 [7]3 years ago
6 0

Answer: For a fixed mass of gas at constant temperature, the volume is inversely proportional to the pressure. That means that, for example, if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.

Explanation:

almond37 [142]3 years ago
5 0
B decreases. I Think at least
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Select the structure that corresponds
Brut [27]

The structure that corresponds to the molecule name - 4-heptanol would be option A.

<h3>Structure of 4-heptanol</h3>

The name, 4-heptanol, indicates that there are 7 carbon atoms in the structure.

In addition, there is also an indication that there is a functional group on the 4th carbon - the alcohol functional group.

Option B has only 6 carbon atoms instead of 7. Option A, on the other hand, fulfills all the criteria.

Thus, A is the correct structure of 4-heptanol.

More on structure of compounds can be found here:brainly.com/question/8155254

#SPJ1

8 0
2 years ago
Be sure to answer all parts. Calculate ΔH o for the following reaction in two ways, using the data given below. H2(g) + I2(g) →
Fantom [35]

Answer:

a) ΔH°rxn = -9.2kJ/mol

b) ΔH°rxn = -9.2kJ/mol

Explanation:

Using Hess's law, you can find ΔH of a reaction from ΔH of formation of the substances involved in the reaction, thus:

ΔH°rxn = ∑(BE(reactants)) − ∑(BE(products))

Or:

ΔH°rxn = ∑(nΔH°f (products)) − ∑(mΔH°f (reactants))

For the reaction:

H₂(g) + I₂(g) → 2HI(g)

a) Using the first equation:

ΔH°rxn = ΔH (H-H) + ΔH (I-I) - 2ΔHBE (H-I)

ΔH°rxn = 436.4kJ + 151kJ - 2×298.3kJ

<em>ΔH°rxn = -9.2kJ/mol</em>

<em />

b) Using the second equation:

ΔH°rxn = 2Δ°f (HI) − ΔH°f (H₂) - ΔH°f (I₂)

ΔH°rxn = 2×25.9kJ - 0kJ - 61.0kJ

<em>ΔH°rxn = -9.2kJ/mol</em>

<em />

7 0
3 years ago
Describe the properties of oobleck when it behaves like a solid and a liquid.
PSYCHO15rus [73]

Answer:

hope it's help you ok have a good day

7 0
3 years ago
Use the balanced equation given below to solve the problem that follows: Calculate the mass in grams of water produced along wit
saveliy_v [14]

Answer: 1.98 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}  

\text{Moles of} CO_2=\frac{5.0L}{22.4L}=0.22moles

The balanced given equation is:

C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)  

According to stoichiometry :

4 moles of CO_2 will produce =  2 moles of H_2O

Thus 0.22 moles of CO_2 will produce=\frac{2}{4}\times 0.22=0.11moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.11moles\times 18g/mol=1.98g

Thus 1.98 g of water is produced along with 5.0 L of CO_2 at STP

6 0
3 years ago
Adding solvent or removing solute from a soltuion is called __________, and a solution is said to be _______________ if it has m
xenn [34]
Adding solvent or removing solute from a solution is called diluting. And a solution is said to be concentrated if it has more solute. The opposite of diluting is called concentrating. The measure of the amount of solute in a solution is expressed in concentration.
7 0
3 years ago
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