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Marianna [84]
4 years ago
15

The incomplete table below shows selected characteristics of gas laws.

Chemistry
2 answers:
Elenna [48]4 years ago
6 0

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

P\propto \dfrac{1}{V}

PV=k

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

V\propto T

V=kT

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

\dfrac{PV}{T}=k

Hence, this is the required solution.

Sedaia [141]4 years ago
5 0

Answer :

Name: Boyle's Law

Variables: pressure and volume

Constants: moles of gas  and temperature

Equation: PV = k

Name: Charles’s law

Variables: Volume and temperature

Constants: moles of gas  and pressure

Equation: V = kT

Name: Gay-Lussac's Law

Variables: Temperature, pressure

Constants: moles of gas  and volume

Equation: P = kT

Name: Combined gas law

Variables: Pressure, temperature, volume

Constants: Gas constant and moles of gas

Equation: PV=kT

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}\\\\PV=k

Charles' Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T\\\\V=kT

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T\\\\P=kT

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

PV\propto T\\\\PV=kT

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Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

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Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

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5 0
1 year ago
The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

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⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

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⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

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