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yuradex [85]
4 years ago
5

Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air

to 8 m underwater. How has the change in media affected the frequency of the wave?
Physics
2 answers:
Alja [10]4 years ago
7 0

Answer:

the answer is c

Explanation:

frosja888 [35]4 years ago
3 0

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

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An iron Tyre of diameter 50cm at 288k is to be shrank on to a wheel of diameter 50.35cm.To what temperature must the tyre be hea
hichkok12 [17]

Answer:

The answer should be D

Explanation:

8 0
3 years ago
When the displacement of a mass on a spring is 12 A, what percentage of the energy is kinetic energy?
Zolol [24]

Answer:

1.44%

Explanation:

The potential energy of a spring is given by

U=\dfrac{1}{2}kx^2

The kinetic energy is

E=\dfrac{1}{2}kA^2

Now x = 12 A

Applying in the first equation

U=\dfrac{1}{2}k(12A)^2\\\Rightarrow U=\dfrac{1}{2}k144A^2\\\Rightarrow U=144\dfrac{1}{2}kA^2\\\Rightarrow U=144E

The percentage would be 14400%

at x=\dfrac{1}{2}A (makes more sense)

U=\dfrac{1}{2}k(\dfrac{1}{2}A)^2\\\Rightarrow U=\dfrac{1}{2}k\dfrac{1}{4}A^2\\\Rightarrow U=\dfrac{1}{4}\times \dfrac{1}{2}kA^2\\\Rightarrow U=0.25E

The percentage is 25 % of the kinetic energy

6 0
3 years ago
How many coulombs of charge do 50 * 10^31 electrons possess
Angelina_Jolie [31]
Quantity of Charge , Q = ne
Where n = number of electrons
             e = charge on one electron = -1.6 * 10 ^-19  C.
             n = 50 * 10^31  electrons

Q =    (50 * 10^31)*( -1.6 * 10 ^-19 ) =  -8 * 10^13 C.

Note that the minus sign indicates that the charge is a negative charge.
7 0
4 years ago
Leght of a chief of a circle
WINSTONCH [101]

Answer: Your question does not make sense

Explanation:

4 0
4 years ago
A box contains about 5.54 1021 hydrogen
Aleks [24]

Answer:E=33.71\ J

Explanation:

Given

No of atoms of hydrogen N=5.54\times 10^{21}

Temperature of room T=21^{\circ}\approx 294\ K

Thermal energy of the atoms is given by

E=\frac{3}{2}NkT

where k=boltzmann constant

E=\frac{3}{2}\times 5.54\times 10^{21}\times 1.38\times 10^{-23}\times 294

E=33.71\ J

Hence the energy of the atoms is 33.71\ J

5 0
3 years ago
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