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yuradex [85]
3 years ago
5

Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air

to 8 m underwater. How has the change in media affected the frequency of the wave?
Physics
2 answers:
Alja [10]3 years ago
7 0

Answer:

the answer is c

Explanation:

frosja888 [35]3 years ago
3 0

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

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The period of a pendulum is measured 16 times. The average value of the period over these 16 trials is calculated to be 1.50 sec
marin [14]

Answer:

The additional trials needed is 48 trials

Explanation:

Given;

initial number of trials, n = 16 trials

the standard deviation, σ = 0.24 s

initial standard error, ε = 0.06 s

The standard error is given by;

\epsilon = \frac{\sigma}{\sqrt{n} }

To reduce the standard error to 0.03 s, let the additional number of trials = x

0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials

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6 0
3 years ago
Human-Powered Flight Human-powered aircraft require a pilot to pedal, as in a bicycle, and produce a sustained power output of a
alukav5142 [94]

Answer:

# of Snickers bars 2

Explanation:

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Since power is work divided by time, then work is:

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Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

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To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

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Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

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