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Step2247 [10]
3 years ago
13

Distance = 6 km south 60 minutes What was the average velocity

Physics
2 answers:
shutvik [7]3 years ago
8 0

For this case we have to by definition:

v = \frac {x} {t}

Where:

v: Velocity

x: Distance traveled

t: Time

According to the data we have:

x = 6 \ km = 6000 \ m\\t = 60 \ min = 3600 \ s

So:

v = \frac {6} {60} = 0.1  \frac {km} {min}

Equivalent to:

v = \frac {6000} {3600} = 1.67 \frac {m} {s}

Answer:

0.1 \frac {km} {min}

blsea [12.9K]3 years ago
3 0

v = x/t

v = average velocity, x = displacement, t = elapsed time

Given values:

x = 6km south, t = 60min

Plug in and solve for v:

v = 6/60

v = 0.1km/min south

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During a very quick stop, a car decelerates at 6.8 m/s^2. Assume the forward motion of the car corresponds to a positive directi
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Answer:

-24.28571 rad/s²

29.57239 revolutions

3.91176 seconds

52.026478 m

Explanation:

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\omega_i = Initial angular velocity = 95 rad/s

\theta = Angle of rotation

\omega_f = Final angular velocity

t = Time taken

Angular acceleration is given by

\alpha=\frac{a_t}{t}\\\Rightarrow \alpha=\frac{-6.8}{0.28}\\\Rightarrow \alpha=-24.28571\ rad/s^2

The angular acceleration is -24.28571 rad/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-95^2}{2\times -24.28571}\\\Rightarrow \theta=185.80885\ rad=185.80885\times \frac{1}{2\pi}\\\Rightarrow \theta=29.57239\ rev

The number of revolutions is 29.57239

\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-95}{-24.28571}\\\Rightarrow t=3.91176\ s

The time it takes for the car to stop is 3.91176 seconds

Linear distance

s=r\theta\\\Rightarrow s=0.28\times 185.80885\\\Rightarrow s=52.026478\ m

The distance the car travels is 52.026478 m

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3 years ago
A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
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Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

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3 years ago
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Answer:
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Question 1 of 7What is the change in internal energy if 90 J of thermal energy is added to asystem, and the system does 30 J of
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Given:

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The work done by the system on the surroundings is W = 30 J

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