Distance = 6 km south
60 minutes
What was the average velocity
2 answers:
For this case we have to by definition:
Where:
v: Velocity
x: Distance traveled
t: Time
According to the data we have:
So:
Equivalent to:
Answer:
v = x/t
v = average velocity, x = displacement, t = elapsed time
Given values:
x = 6km south, t = 60min
Plug in and solve for v:
v = 6/60
v = 0.1km/min south
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Answer:
Explanation:
The given data :-
- Diameter of rod AB ( d₁ ) = 200 mm.
- Diameter of rod BC ( d₂ ) = 150 mm.
- The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C
- The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
- Consider the required temperature increase to close the gap at C = T °C
- Consider the change in length of the rod = бL
Solution :-
![\begin{aligned}\delta L&= (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\0& = (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\&=\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{AB}+\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{BC}\\&=2\:\alpha\:T\:L-\frac{L}{E}(\sigma_{AB}+\sigma_{BC})\\T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdelta%20L%26%3D%20%28%5Cdelta%20L%20_%7Bthermal%7D%20%2B%5Cdelta%20L_%7Baxial%7D%29_%7BAB%7D%20%2B%20%28%20%5Cdelta%20L%20_%7Bthermal%7D%20%2B%5Cdelta%20L_%7Baxial%7D%29_%7BBC%7D%5C%5C0%26%20%3D%20%28%5Cdelta%20L%20_%7Bthermal%7D%20%2B%5Cdelta%20L_%7Baxial%7D%29_%7BAB%7D%20%2B%20%28%20%5Cdelta%20L%20_%7Bthermal%7D%20%2B%5Cdelta%20L_%7Baxial%7D%29_%7BBC%7D%5C%5C%26%3D%5Cleft%5B%5Calpha%5C%3AT%5C%3AL%2B%5Cleft%28%5Cfrac%7B-RL%7D%7BAE%7D%5Cright%29%5Cright%5D_%7BAB%7D%2B%5Cleft%5B%5Calpha%5C%3AT%5C%3AL%2B%5Cleft%28%5Cfrac%7B-RL%7D%7BAE%7D%5Cright%29%5Cright%5D_%7BBC%7D%5C%5C%26%3D2%5C%3A%5Calpha%5C%3AT%5C%3AL-%5Cfrac%7BL%7D%7BE%7D%28%5Csigma_%7BAB%7D%2B%5Csigma_%7BBC%7D%29%5C%5CT%26%3D%5Cfrac%7B%5Csigma_%7BAB%7D%2B%5Csigma_%7BBC%7D%7D%7B2%5Calpha%20E%7D%5Cend%7Baligned%7D)
The answer is c have a good day
Perimeter=26in
Area would be to multiply the units together
for a solid cylinder:
for a hollow cylinder:
I will look at the case of a hollow cylinder:
That is as far as i get.
I think it will be the one with the more inertia
im not sure but hope this somewhat helped
