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sukhopar [10]
3 years ago
11

During radioactive decay, ___ energy was transformed to ____

Physics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

Potential energy is transfer to kinetic energy,

If radio active substance is decayed.

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YALL PLEASE PLEASE HELP IF YOU KNOE THE ANSWER TO BOTH OF THEM IT WILL BE VERY NICE PLEASE HELP
Juliette [100K]

Answer:

2.5m/s²

Force  = mass x acceleration  

Explanation:

Given parameters

Mass  = 200kg

Force  = 500N

Unknown:

Acceleration  = ?

Solution:

According to the Newton's second law of motion "the constant force applied on a massive body causes it to accelerate".

 Mathematically;

    Force  = mass x acceleration  

Now insert the parameters and solve;

   Acceleration  = \frac{force}{mass}  

   Acceleration = \frac{500}{200}   = 2.5m/s²

8 0
2 years ago
Select the correct answer.
chubhunter [2.5K]
I believe it’s self-referent encoding
3 0
2 years ago
Is this right or they wrong definitions which ones are the right ones someone !!!!!
Alex73 [517]

Answer:

They are right.

Explanation:

4 0
3 years ago
Read 2 more answers
A manometer is used to measure the air pressure in a tank. The fluid used has a specific gravity of 1.25, and the differential h
Sloan [31]

Answer:

77.88 lbm/ft³

Explanation:

Given,

Specific gravity, SG = 1.25

Density of water, ρ = 62.30 lbm/ft³

density of the fluid =

   = S.G x ρ_{water}

   = 62.30 x 1.25

   = 77.88 lbm/ft³

Density of the fluid is equal to 77.88 lbm/ft³

3 0
3 years ago
Conductivities are often measured by comparing the resistance of a cell filled with the sample to its resistance when filled wit
Bezzdna [24]

Answer:

1200 Sm^2mol^-1

Explanation:

Given data :

conductivity of water ( kwater ) = 76 mS m^-1 = 0.076 Sm^-1

conductivity of kcl (aq)( Kkcl ) = 1.1639 Sm^-1

Kkcl = 1.1639 - 0.076 = 1.0879  Sm^-1

Resistance = 33.21 Ω

where conductivity can be expressed as = \frac{Cell constant}{Resistance }

hence cell constant = conductivity * Resistance

                                 = 1.0879 * 33.21 = 36.13m^-1

conductivity of  CH3COOH ( kCH3COOH ) =  36.13 / 300

                                                                       = 0.120 Sm^-1

<u>Determine the molar conductivity of acetic acid</u>

= ( kCH3COOH * 1000 ) / C

C = 0.1 mol dm

=  (0.120 * 1000) / 0.1  =  1200 Sm^2mol^-1

3 0
3 years ago
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