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Olenka [21]
3 years ago
6

Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, t

his gun accelerates a 3.8-kg projectile from rest to a speed of 9.3 × 103 m/s. The net force accelerating the projectile is 9.3 × 105 N. How much time is required for the projectile to come up to speed?
Physics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

t=0.038s

Explanation:

Project mass m=3.8 kg

Initial speed vi= 0m/s

Final speed vf= 9.3×10³ m/s

Force F=9.3×10⁵N

To find

Time t

Solution

From Newtons second law we know that

∑F=ma

Where m is mass

a is acceleration

We can write this equation as

∑F=m(Δv/Δt)

=m\frac{v_{f}-v_{i}}{t}

Rearrange this equation to find time t

So

t=m\frac{v_{f}-v_{i}}{F}

Substitute the given values

t=3.8kg\frac{9.3*10^3m/s-0}{9.3*10^5N} \\t=0.038s  

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Please Mark Brainliest If This Helped!

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2 years ago
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Answer:

Incomplete question

This is the completed question

If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?

Explanation:

Using ohms law as our basis

Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current

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a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.

From ohms law

V=iR

When v =1.5V

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When V increase to 12V

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I.e, it increases by a factor of 8. Eight times it's initial value

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6 0
3 years ago
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Answer:

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Explanation:

From the diagram below; we would notice that the Force (F) = Tension (T)

Also the angle θ adjacent to the perpendicular line = 90 °

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