Answer:
As we have already discussed earlier, motion is the state of change in position of an object over time. It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion. The relations between these quantities are known as the equations of motion.
Answer:
Stretch in the spring = 0.1643 (Approx)
Explanation:
Given:
Mass of the sled (m) = 9 kg
Acceleration of the sled (a) = 2.10 m/s
²
Spring constant (k) = 115 N/m
Computation:
Tension force in the spring (T) = ma
Tension force in the spring (T) = 9 × 2.10
Tension force in the spring (T) = 18.9 N
Tension force in the spring = Spring constant (k) × Stretch in the spring
18.9 N = 115 N × Stretch in the spring
Stretch in the spring = 18.9 / 115
Stretch in the spring = 0.1643 (Approx)
Average speed = (distance covered) / (time to cover the distance)
Average speed = (4 meters) / (5 seconds)
Average speed = (4/5) (meters/seconds)
Average speed = 0.8 m/s
Answer:
A=ACCELERATION = -4 m/s^2
B=DISTANCE= 72 m
Explanation:
Solving for the acceleration of the car
A= (10 m/s-30 m/s) / 5s
A= -20 m/s / 5s
A= -4 m/s^2
Solving for the distance traveled after the third second
D= v1 * t + 1/2at^2
D= 30 m/s * 3 s + -2m/s^2 * (3s)^2
D= 90 m + - 18 m
D = 72 m
Answer: 50 m
Consider the figure below: Let O be the starting reference point. The boy runs northwards 125 m and then 75 m southwards.
Displacement is the shortest path traveled from the reference point. Distance is the total path length traveled. Hence, the distance would be 125 +75 =200 m but the displacement would be 
.
