Answer:
the <em>ratio F1/F2 = 1/2</em>
the <em>ratio a1/a2 = 1</em>
Explanation:
The force that both satellites experience is:
F1 = G M_e m1 / r² and
F2 = G M_e m2 / r²
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- r is the orbital radius
- M_e is the mass of Earth
Therefore,
F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]
F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]
F1/F2 = m1/m2
F1/F2 = 1000/2000
<em>F1/F2 = 1/2</em>
The other force that the two satellites experience is the centripetal force. Therefore,
F1c = m1 v² / r and
F2c = m2 v² / r
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- v is the orbital velocity
- r is the orbital velocity
Thus,
a1 = v² / r ⇒ v² = r a1 and
a2 = v² / r ⇒ v² = r a2
Therefore,
F1c = m1 a1 r / r = m1 a1
F2c = m2 a2 r / r = m2 a2
In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,
F1 = F1c
G M_e m1 / r² = m1 a1
a1 = G M_e / r²
also
a2 = G M_e / r²
Thus,
a1/a2 = [G M_e / r²] / [G M_e / r²]
<em>a1/a2 = 1</em>
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According to the saving of the momentum, the total momentum before collision is equal to the total momentum after collision
<em><u>in symbols:</u></em>
<em>
</em>
thus

then, the initial momentum of the second cart

Answer:
The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s
Explanation:
given information:
B = 0.5 mT = 0.0005 T
N = 1000
r = 5 cm = 0.05 m
emf, ε = 1 V
according to Faraday's law
ε = -N dΦ/dt, Φ = B A
= - N d( B A)/dt
= - N d( B A cos ωt)/dt
= - N B A d(cos ωt)/dt
= N B A ω sin ωt
A = πr², so
ε = N B πr² ω sin ωt
where
ε = emf
N = number of coil turn
B = magnetic field
r = radius
ω = angular velocity
Φ = magnetic flux
emf maximum, sin ωt = 1. So,
ε = N B πr² ω
ω = ε/N B πr²
= 1/[(1000) (0.0005) π (0.05)²
= 254.65 rad/s
Answer:
600 m
Explanation:
Distance = speed × time
= (15)(40)
= <u>6</u><u>0</u><u>0</u><u> </u><u>m</u>