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Olenka [21]
3 years ago
6

Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, t

his gun accelerates a 3.8-kg projectile from rest to a speed of 9.3 × 103 m/s. The net force accelerating the projectile is 9.3 × 105 N. How much time is required for the projectile to come up to speed?
Physics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

t=0.038s

Explanation:

Project mass m=3.8 kg

Initial speed vi= 0m/s

Final speed vf= 9.3×10³ m/s

Force F=9.3×10⁵N

To find

Time t

Solution

From Newtons second law we know that

∑F=ma

Where m is mass

a is acceleration

We can write this equation as

∑F=m(Δv/Δt)

=m\frac{v_{f}-v_{i}}{t}

Rearrange this equation to find time t

So

t=m\frac{v_{f}-v_{i}}{F}

Substitute the given values

t=3.8kg\frac{9.3*10^3m/s-0}{9.3*10^5N} \\t=0.038s  

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H20 (water) is an example of a __, as it is made up of two elements.
vova2212 [387]

Answer:

Compound.

Explanation:

A compound is a substance formed when two or more elements are chemically joined. Water, salt, and sugar are examples of compounds. When the elements are joined, the atoms lose their individual properties and have different properties from the elements they are composed of.

8 0
3 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
3 years ago
Read 2 more answers
PLEASE HELP! thxssss<br>​
Cerrena [4.2K]

Answer:

D is correct

Explanation:

5 0
3 years ago
How much work, in Joules, is required to stop a 1,168 kg car moving with a speed of 24 km/hr?
ANEK [815]
24km/hour=(20/3)m/s
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J

6 0
2 years ago
An 19.2-cm-long bicycle crank arm, with a pedal at one end is attached to a 20.6-cm-diameter sprocket, the toothed disk around w
Anon25 [30]

Answer:

0.0545 m/s2

Explanation:

19.2 cm = 0.192 m

We can convert rpm (revolution per minute) to angular velocity rad/s knowing that each revolution is 2π rad and each minute is 60 seconds.

57 rpm = 57 * 2π / 60 = 6 rad/s

86 rpm = 86 * 2π / 60 = 9 rad/s

The angular acceleration of the sprocket is the change in angular velocity per unit of time

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{9 - 6}{10.7} = 0.284 rad/s^2

The tangential acceleration of the pedal is the product of its angular acceleration and the radius of rotation, aka the pedal arm length L = 0.192 m

a_T = \alpha*L = 0.284*0.192 = 0.0545 m/s^2

3 0
3 years ago
Read 2 more answers
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