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Serjik [45]
3 years ago
15

A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is release

d, it accelerates upward with an acceleration of 24 m/s^2. What is the charge on the bead?
Physics
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

The charge on the bead is  q = 6.084 *10^{-7}\ C

Explanation:

From the question we are told that

     The  mass of the bead is  m  =  3.6 \ g =  0.0036 \ kg

      The  magnitude of the electric field is  E =  200,000 \ N/C

       The  acceleration of the bead is  a =  24 m/s^2

Generally,  the  electric force on the bead is  mathematically represented as  

         F_ e =  q E

Where q is the charge on the bead

   Now the gravitational force opposing the upward movement of the bead is  mathematically represented as

       F_g  =  mg

Generally the net force on the bead is  mathematically represented as

       F  =  F_e - F_g = m* a

=>    qE -  mg  = ma

Now substituting values

       q *  200000 -   0.0036 *9.8   = 0.0036 * 24

     q = 6.084 *10^{-7}\ C

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umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

4 0
3 years ago
Please help with this :(
Rainbow [258]

Answer:

I don't really know but i have an idea

Explanation:

so acceleration means: increase in the rate or speed of something.

so just a head start.

your welcome!!

3 0
2 years ago
Conductivities are often measured by comparing the resistance of a cell filled with the sample to its resistance when filled wit
Bezzdna [24]

Answer:

1200 Sm^2mol^-1

Explanation:

Given data :

conductivity of water ( kwater ) = 76 mS m^-1 = 0.076 Sm^-1

conductivity of kcl (aq)( Kkcl ) = 1.1639 Sm^-1

Kkcl = 1.1639 - 0.076 = 1.0879  Sm^-1

Resistance = 33.21 Ω

where conductivity can be expressed as = \frac{Cell constant}{Resistance }

hence cell constant = conductivity * Resistance

                                 = 1.0879 * 33.21 = 36.13m^-1

conductivity of  CH3COOH ( kCH3COOH ) =  36.13 / 300

                                                                       = 0.120 Sm^-1

<u>Determine the molar conductivity of acetic acid</u>

= ( kCH3COOH * 1000 ) / C

C = 0.1 mol dm

=  (0.120 * 1000) / 0.1  =  1200 Sm^2mol^-1

3 0
3 years ago
A planet orbits a start with the path shown below.
kvv77 [185]

PART a)

As we know that gravitational potential energy is given by the formula

U = -\frac{Gm_1m_2}{r}

here we can see that gravitational potential energy inversely varies with the distance

so here when distance from the sun is minimum then magnitude of gravitational potential energy is maximum while since it is given with negative sign so its overall value is minimum at that position

So gravitational potential energy is minimum at the nearest point and maximum at the farthest point

PART b)

Since we know that sum of kinetic energy and potential energy is constant here

so the points of minimum potential energy is the point where kinetic energy is maximum which means speed is maximum

So here speed is maximum at the nearest point

Part C)

since gravitational potential energy inversely varies with distance so it's graph will be like hyperbolic graph with distance

4 0
3 years ago
An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
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