The answer true I’m guessing. It’s a 50/50 chance
To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.
PART A) Normal Force.
![F_n = \frac{mv^2}{r}](https://tex.z-dn.net/?f=F_n%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![N+mgcos\theta = \frac{mv^2}{r}](https://tex.z-dn.net/?f=N%2Bmgcos%5Ctheta%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
Here,
Normal reaction of the ring is N and velocity of the ring is v
![N+mgcos\theta = \frac{mv^2}{r}](https://tex.z-dn.net/?f=N%2Bmgcos%5Ctheta%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})](https://tex.z-dn.net/?f=N%2BWcos%5Ctheta%20%3D%20%5Cfrac%7BW%7D%7Bg%7D%20%28%5Cfrac%7Bv%5E2%7D%7Br%7D%29)
![N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}](https://tex.z-dn.net/?f=N%2B2cos30%5C%C2%B0%20%3D%20%5Cfrac%7B2%7D%7B32.2%7D%2A%5Cfrac%7B10%5E2%7D%7B2%7D)
![N = 1.374lb](https://tex.z-dn.net/?f=N%20%3D%201.374lb)
PART B) Acceleration
![F_t = ma_t](https://tex.z-dn.net/?f=F_t%20%3D%20ma_t)
![-mgsin\theta = ma_t](https://tex.z-dn.net/?f=-mgsin%5Ctheta%20%3D%20ma_t)
![-W sin\theta = \frac{W}{g} a_t](https://tex.z-dn.net/?f=-W%20sin%5Ctheta%20%3D%20%5Cfrac%7BW%7D%7Bg%7D%20a_t)
![-2Sin30\° = (\frac{2}{32.2})a_t](https://tex.z-dn.net/?f=-2Sin30%5C%C2%B0%20%3D%20%28%5Cfrac%7B2%7D%7B32.2%7D%29a_t)
![a_T = -16.10ft/s^2](https://tex.z-dn.net/?f=a_T%20%3D%20-16.10ft%2Fs%5E2)
Negative symbol indicates deceleration.
<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>
Answer:
Option A
D = m/v
Explanation:
Density is defined as mass per unit volume of an object. Therefore, D=m/v where m is the mass of the object and v is the volume
Therefore, option A is the right option
Heat equation, Q = m.c.Δt
Here, c represents " the specific heat of the substance "
Hope this helps!