What is 1+2...................
1 answer:
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<u>Answer:</u> The equilibrium concentration of is 0.332 M
<u>Explanation:</u>
We are given:
Initial concentration of = 2.00 M
The given chemical equation follows:
<u>Initial:</u> 2.00
<u>At eqllm:</u> 2.00-2x x x
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible
So, equilibrium concentration of
Hence, the equilibrium concentration of is 0.332 M
- 13mol of O_2 reacts with 2mols of C_4H_10.
- 7.5mol of O_2 reacts with 1mol of C_4H_10
No of moles:-
Now
Moles of O_2
Mass of O_2