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3 years ago

How can you use unit rates to solve pricing problems?

Mathematics

2 answers:

melomori [17]3 years ago

5 0

Answer:

a ratio is a comparison of two numbers or measurements

the objects being compared are called the terms of the ratio.

if the tow terms are different units this is called a rate.

example:

David covers 600 miles in 8 hours and John covers 380 miles in 5 hours. Who is driving faster ?

solution:

Distance covered by David in 1 hour is

= 600 / 8

= 75 miles per hour

Distance covered by John in 1 hour is

= 380 / 5

= 76 miles per hour

When we compare the above unit rates (Distance covered in 1 hour), John is driving faster than David.

Llana [10]3 years ago

3 0

We can use unit rates to solve pricing problems because we solve for price of one of that item.

For example, David bought 5 pounds of peanuts for $10, how much does it cost for one pound?

10 / 5 = $2 per pound

The $2 is the unit rate and we use to find if David buys more then 10 pounds.

Best of Luck!

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The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery tim

Hatshy [7]

Answer:

The expected cost is 152

Step-by-step explanation:

Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y

$f_Y(y ) = \frac{1}{5-1} = \frac{1}{4}$ if $1\leq y \leq 5$ and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)

Recall that, by definition

$E(Y^k) = \int_{-\infty}^{\infty} y^kf_Y(y)dy$

Also, we are given that $C = 50+3Y+9Y^2$ . Recall the following properties of the expected value. If X,Y are random variables, then

$E(a+bX+cY) = a+bE(X)+cE(Y)$

Then, using this property we have that $E[C] = 50+3E[Y]+ 9E[Y^2]$ .

Thus, we must calculate E[Y] and E[Y^2].

Using the definition, we get that

$E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3$

$E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}$

Then

$E(C) = 50 + 3\cdot 3 + 9 \cdot \frac{31}{3} = 152$

5 0

3 years ago

Really need helpllllll!!!!!

kirza4 [7]

Answer:

The relationship of the number of months and the total amount paid is proportional for both Hanks and Lynn.

Step-by-step explanation:

Let us divide the equation into 2 parts.

Hanks

Hank paid $2000 up front when he bought the car and he pays $200 every month. Therefore, the total amount paid (y) and the number of month (x)can be expressed as follows.

Let

x = number of month

y = total amount paid

y = 2000 + 200x

The relationship between amount paid and the number of months is proportional

Lynn

She did not paid anything upfront but she paid $275 every month. Therefore,

x = number of month

y = total amount paid

y = 275x

This relationship between amount paid and number of month is directly proportional

7 0

3 years ago

Mrs. Jackson spends $ 18 for 3 pound how many was it per pound

Artyom0805 [142]

Answer: 6 dollars per pound

Step-by-step explanation:

You just divide 18/3 and you get your answer! Give me brainliest pleass!

7 0

2 years ago

7. A line of symmetry divides a design so that every point on one side of the line

SVEN [57.7K]

Answer:

ok here is the answer 3 3/6

Step-by-step explanation:

4 0

3 years ago

The line plot shows amount of miles students ran in a week. What is the difference in the lowest miles and the highest miles run

shepuryov [24]

Answer:

Step-by-step explanation:

There are 4 lines in between 2 consecutive integers, so each division is:

1/4 = 0.25

As we see from the graph, the highest miles is at the division before 2, which is 1.75

Also, the lowest miles is at 0.

Hence, difference in highest and lowest is 1.75 - 0 = 1.75

In fraction, $1.75=1\frac{3}{4}$

correct answer C

8 0

3 years ago

How can you use unit rates to solve pricing problems?​

How can you use unit rates to solve pricing problems?