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seropon [69]
3 years ago
13

How can you use unit rates to solve pricing problems?​

Mathematics
2 answers:
melomori [17]3 years ago
5 0

Answer:

a ratio is a comparison of two numbers or measurements

the objects being compared are called the terms of the ratio.

if the tow terms are different units this is called a rate.

example:

David covers 600 miles in 8 hours and John covers 380 miles in 5 hours. Who is driving faster ?

solution:

Distance covered by David in 1 hour is

=  600 / 8  

=  75 miles per hour

Distance covered by John in 1 hour is

=  380 / 5  

=  76 miles per hour

When we compare the above unit rates (Distance covered in 1 hour), John is driving faster than David.

Llana [10]3 years ago
3 0

We can use unit rates to solve pricing problems because we solve for price of one of that item.

For example, David bought 5 pounds of peanuts for $10, how much does it cost for one pound?

10 / 5 = $2 per pound

The $2 is the unit rate and we use to find if David buys more then 10 pounds.

Best of Luck!

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What is the area of the triangle below?
Nady [450]

Answer:

36

Step-by-step explanation:

1/2 × b× h

= 1/2 × 9×8

= 9×4

= 36 sq. in

7 0
3 years ago
Find the difference.<br> 6rs − 2rs
lara [203]
6rs - 2rs = 4rs 
The word difference means subtract
Not sure why you needed help lol
5 0
2 years ago
Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half.
yKpoI14uk [10]
Basically, the parabola has to have all points that are equidistant from the focus and the directrix, the directrix being a horizontal line, and the focus being a point given. To derive an equation from this you need to use the distance formula which I'm guessing you already know because you're already in precalc.
The gist of it is that we have a random point on the parabola (x,y), and the point (x,y) will be equidistant from both the focus and the directrix. If we use the distance formula, you get something like this:
\sqrt{(y-(- \frac{1}{2} ))^2} = \sqrt{(x-2)^2+(y-(-1)^2}
The square root of y-(-1/2) coming from the directrix, and the righthand side of the equal sign being derived from the focus.
All you need to do is simplify now!
<span>(y+\frac{1}{2})^2 = (x-2)^2+(y+1)^2 \\\ y^2+y+ \frac{1}{4} = x^2-4x+4 + y^2+2y+1 \\\ -y-\frac{3}{4} = x^2-4x+4 \\\ -y-\frac{3}{4} = (x-2)^2 \\\ -y = (x-2)^2+\frac{3}{4} \\\ y = -(x-2)^2-\frac{3}{4}
</span>
Hope I helped! 
3 0
3 years ago
Read 2 more answers
Match each expression with an equivalent expression.
Marysya12 [62]

Answer:

6x-4y →  4.  2(3x-2y)

6-4x →    3.  2(3-2x)

6x-4x →  1. 2x

6x-4 →   2. 2(3x-2)

Step-by-step explanation:

You need to:

 Factor out 2 from 6x-4y,  then you get the equivalent expression:

=2(3x-2y) this matches with OPTION 4

Factor out 2 from 6-4y, then you get the equivalent expression:

=2(3-2x) this matches with OPTION 3

Make the subtraction for 6x-4x,  then you get the equivalent expression:

=2x this matches with OPTION 1

Factor out 2 from 6x-4,  then you get the equivalent expression:

=2(3x-2) this matches with OPTION 2

3 0
2 years ago
Read 2 more answers
On a road map, the locations A, B and C are collinear. Location C divides the road from location A to B, such that AC:CB = 1:2.
koban [17]

Answer:

C. (-1,-2)

Step-by-step explanation:

Since C internally divides AB in the ratio AC/CB = 1/2 = m/n where m = 1 and n = 2, we use the formula for internal division.

Let A = (x₁, y₁) = (5, 16), B = (x₂, y₂) and C = (x, y) = (3, 10)

So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

Substituting the values of the coordinates, we have

x = (mx₂ + nx₁)/(m + n)

3 = (1 × x₂ + 2 × 5)/(2 + 1)

3 = (x₂ + 10)/3

multiplying through by 3, we have

9 = x₂ + 10

x₂ = 9 - 10

x₂ = -1

y = (my₂ + ny₁)/(m + n)

10 = (1 × y₂ + 2 × 16)/(2 + 1)

10 = (x₂ + 32)/3

multiplying through by 3, we have

30 = y₂ + 32

y₂ = 30 - 32

y₂ = -2

So, the coordinates of B are (-1, -2)

3 0
2 years ago
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