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Lena [83]
4 years ago
6

Please help! Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pi

ctured. What would be the frequency produced by the speakers to create perfectly constructive interference? Assume n = 1 and v = 343 m/s.
213.04 Hz

256.70 Hz

186.68 Hz

233.14 Hz

Physics
2 answers:
bonufazy [111]4 years ago
6 0

Answer:

213.04 Hz

Explanation:

xz_007 [3.2K]4 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Using the Pythagoras theorem, we will calculate the the distance of S_{1}P and S_{2}P as follows.

        S_{1}P = \sqrt{(10)^{2} + (22)^{2}}

                   = 24.17

        S_{2}P = \sqrt{(5)^{2} + (22)^{2}}

                   = 22.56

Therefore, the path difference will be as follows.

           \Delta r = S_{1}P - S_{2}P

                      = 24.17 - 22.56

                      = 1.61 m

Formula for constructive interference is as follows.

                   \Delta r = n \lambda

                      \lamda = 1.61 m      (for n = 1)  

Therefore, frequency will be calculated as follows.

                  \nu = \frac{v}{\lambda}

                            = \frac{343}{1.61}

                            = 213.043 Hz

Thus, we can conclude that frequency produced by the speakers to create perfectly constructive interference is 213.04 Hz.

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