Answer:
 spring deflection is  x = (v2 / R + g) m / 4
Explanation:
We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration
  
Let's write the equations on the Y axis of this description
        Fe - W = m 
Where Fe is elastic force, W the weight and  the centripetal acceleration. The elastic force equation is
  the centripetal acceleration. The elastic force equation is
        Fe = - k x
       
        4 (k x) - mg = m v² / R
The four is because there are four springs, R is theradio of dip
We can calculate the deflection (x) of the springs
        x = (m v2 / R + mg) / 4
        
        x = (v2 / R + g) m / 4
 
        
             
        
        
        
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