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2 years ago

What activates a convection current, starting the flow of a fluid ??

Chemistry

2 answers:

kari74 [83]2 years ago

8 0

The answer is D hope this helps

Grace [21]2 years ago

6 0

Hey there!

What activates a convection current, starting the flow of a fluid ?

Answer: 

D. Temperature differences in the mantle 
Hope this helps
Have a great day (:

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Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

Answer: The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

Explanation:

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

Oxidation half reaction: $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

4 0

3 years ago

If you leave a glass of water and ice on the kitchen counter long enough, after a while you will have just a glass of water. why

irakobra [83]

The heat of the water is shared with the ice and there for you drink will get cold but your ice will melt away from the heat going in the ice

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3 years ago

Tia has a sample of pure gold (Au). She weighed the sample and the result was 35.9 grams. Tia wants to determine the number of a

Gemiola [76]

First, find moles of gold given the mass of the sample:
(35.9g Au)/(197.0g/mol Au) = 0.182mol Au

Second, multiply moles of Au by Avogrado's number:
(0.182mol)(6.02 x10^23)= 1.10x10^23 atoms Au

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3 years ago

Read 2 more answers

Which molecules are pure elements?

Elenna [48]

Well none since molecules are a group of two or more atoms electrically bonded with one another. However, there are gases that does not naturally bond due to their stability and can be found in nature as pure elements. But these are not considered as molecules.

(By the way, these gases are the noble gases that can be found on the last column of the periodic table)

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3 years ago

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Determine the volume of atmospheric air (at 14 lb/in.^2) needed to fill your bike tires (assuming it holds 500 mL of air) to the

Fiesta28 [93]

Boyle Law says “the pressure of fixed amount of ideal gas which is at constant temperature is inversely proportional to its volume".

P = 1/V

Where, P is pressure of the ideal gas and V is volume of the ideal gas.

For two situations, this law can be added as;
P₁V₁ = P₂V₂

14 lb/in² x V₁ = 70 lb/in² x 500 mL
V₁ = 2500 mL

Hence, the needed volume of atmospheric air = 2500 mL

Here, we made two assumptions. They are,
1. The atmospheric air acts as ideal gas.
2. Temperature is a constant.

We didn't convert the units to SI units since converting volume and pressure are products of two numbers, they will cut off.

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3 years ago