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MissTica
3 years ago
12

If you wanted to prepare a 15.58 L of a 6.25 M solution, what volume of a 14.73 M solution must you start with?

Chemistry
1 answer:
Fed [463]3 years ago
4 0

Answer:

6.61 L

Explanation:

M1 = 6.25

V1 = 15.58

M2 = 14.73

M1V1 = M2V2

(6.25)(15.58) = (14.73)V2

V2 = 6.61 L

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Explanation:

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3 years ago
The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of
zzz [600]

Answer:

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4 0
3 years ago
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