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katovenus [111]
3 years ago
12

Complete the sentence:

Chemistry
1 answer:
Komok [63]3 years ago
3 0

equilibrium

Heat transfers from a body with high temperature to a body with low temperature until both bodies are in the same temperature.

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PLEASE HELP!
adelina 88 [10]
<span>he balanced equation for the reaction is
4Fe + 3O</span>₂ ---> 2Fe₂O₃<span> 
stoichiometry of O</span>₂ to Fe₂O₃  is 3:2
                   
number of O₂ moles used up - mass present / molar mass of O₂
number of O₂ moles = 63.98 g / 32 g/mol = 1.999 mol
 
if 3 mol of O₂ forms 2 mol of Fe₂O₃  
then 1.999 mol of O₂ forms - 2/3 x 1.999 mol = 1.333 mol
answer is A) 1.333 mol of Fe₂O₃  are formed
7 0
4 years ago
Read 2 more answers
Putting up 98 points! Will give medal
VladimirAG [237]

A calorimeter contains 500 g of water at 25°C.....

the temperature of the water inside the calorimeter is 39.4°C.....

The specific heat of water is 4.18 J/g-°C.

energy needed to heat the water = specific heat * mass * temp difference

= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

4 0
3 years ago
Read 2 more answers
Which equation is balanced in an acidic solution?
liberstina [14]

Answer:

I think C but it could be D

Explanation:

I would say go for C

5 0
3 years ago
Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2
Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has SP^{2}  O has SP^{2} .

Explanation : The orbitals of oxygen and carbon which are involved in SP^{2} hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b:  O SP^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen SP^{3} hydrogen atoms in it. It has SP^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C is SP^{3}  O is also SP^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of SP^{3} hybridized bonds.

Answer 5) Bond d:   C atom has SP^{3}  C atom has SP^{3}

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be SP^{3}. Therefore, the orbitals that undergo SP^{3} hybridization are SP^{3}.

Answer 6) Bond e : C1 containing O SP^{2}    

C2 is SP^{3}

Explanation : The carbon atom which contains oxygen along with a double bond has SP^{2} hybridized orbitals involved in the bonding process; whereas the carbon at C2 has SP^{3} hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0
4 years ago
Whose work directly resulted in the development of and atomic model that has negative electrons stuck within a sea of positive m
raketka [301]
It is the work of J.J Thomson that directly resulted in the development of an atomic model that has negative electrons stuck within a sea of positive material. His proposal was called the plum pludding model. He is the one who discovered electrons.
8 0
3 years ago
Read 2 more answers
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