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Montano1993 [528]
3 years ago
11

Please answer this!!! I will give brainliest!!!

Physics
2 answers:
Oduvanchick [21]3 years ago
4 0

Answer:

The last one

Explanation:

ziro4ka [17]3 years ago
4 0

Answer:

The dotted line from the earth to the moon represents your line of sight when looking at the moon. ... So the basic explanation is that the lunar phases are created by changing angles (relative positions) of the earth, the moon and the sun, as the moon orbits the earth

Explanation:

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A 0.350kg bead slides on a curved fritionless wire,
LuckyWell [14K]

Answer:

h2 = 0.092m

Explanation:

From a balance of energy from point A to point B, we get speed before the collision:

m1*g*h-\frac{m1*V_B^2}{2}=0  Solving for Vb:

V_B=\sqrt{2gh}=6.56658m/s

Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:

V_{B'}=V_B*\frac{m1-m2}{m1+m2} = \sqrt{2gh}* \frac{m1-m2}{m1+m2}=-1.34316m/s

Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:

m1*g*h2-\frac{m1*V_{B'}^2}{2}=0 Solving for h2:

h2 = 0.092m

6 0
3 years ago
Flying against the wind, a jet travels 4640 in 8 hours. flying with the wind, the same jet travels 9000 in 9 hours. what is the
Vanyuwa [196]
17 in wind and 13640 meh buddy
3 0
3 years ago
A rock thrown with speed 8.50 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 19.0 m bef
frez [133]
Draw a diagram to illustrate the problem as shown below.

The vertical component of the launch velocity is
v = (8.5 m/s)*sin30° = 4.25 m/s
The horizontal component of the launch velocity is
8.5*cos30° = 7.361 m/s

Assume that aerodynamic resistance may be ignored.
Because the horizontal distance traveled is 19 m, the time of travel is
t = 19/7.361 = 2.581 s

The downward vertical travel is modeled by
h = (-4.25 m/s)*(2.581 s) + 0.5*(9.8 m/s²)*(2.581 s)²
   = 21.675 m

Answer: The height is 21.7 m (nearest tenth)

4 0
3 years ago
Need help with a Physics math problem.
Bess [88]

Neither of those questions makes sense, and I believe that you should not waste your time worrying about them.

#61 gives you a lot of information about a ball, and then asks a question about a glove.

#62 gives a mysterious equation, doesn't tell you what either of the variables represents, and then asks for a quantity without ever telling us how that quantity is related to the equation.

Personally, my response to both questions would be "Insufficient information given".

3 0
4 years ago
What force is needed to move a 5 kg mass with an acceleration of 5 m/s²?
ElenaW [278]

Answer:

b)25N

Explanation:

F=ma

F=(5kg)(5m/s^2)

F=25N

4 0
2 years ago
Read 2 more answers
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