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polet [3.4K]
3 years ago
13

how do you isolate t (time) in this equation? the question is asking me to derive an equation for time to hit the ground for a d

ropped object in terms of height of the drop, gravity, and initial velocity and that’s what i have so far.

Physics
1 answer:
expeople1 [14]3 years ago
8 0

Fine, so we have the equation

S = So + Vo.t + at²/2

We have the final height = 0 and since its dropped, Vo = 0, our a will be the gravity, negative since its falling

0 = So + 0.t - gt²/2

0 = So - gt²/2

Since So is our h, lets change the letter

0 = h - gt²/2

gt²/2 = h

gt² = 2h

t² = 2h/g

t = \sqrt{\frac{2h}{g}}

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Answer:

Yes

Explanation:

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F = Gm1m2/r²

This is a general physical law derived from

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when distance is doubled the gravitational force will be reduced by quarter not half.

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3 years ago
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What does vitamin c do for our body?
Ksju [112]

Answer:

necessary for the growth, development and repair of all body tissues. it's involved in many body functions, including formation of collagen, absorption of iron, the proper functioning of the immune system, wound healing, and the maintenance of cartilage, bones, and teeth.

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What is the weight of a 48 kg girl on Earth? Rounded to the nearest whole number
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Answer:

471 N

Explanation:

Weight is just another word for the force of gravity.

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so we can simply say

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A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turn
kumpel [21]

Answer:

a) The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

Explanation:

Statement is incomplete. The complete description is now described below:

<em>A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off. </em>

<em>(a) What is the magnitude of the satellite's velocity when the thruster turns off</em>

<em>(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis</em>

Let be x and y-directions orthogonal to each other and the satellite is accelerated uniformly from rest in the +x direction and moves at constant velocity in the +y direction. The velocity vector of the satellite (\vec{v}_{S}), measured in meters per second, is:

\vec{v}_{S} = (v_{o,x}+a_{x}\cdot t)\,\hat{i}+v_{y}\,\hat{j}

Where:

v_{o,x} - Initial velocity in +x direction, measured in meters per second.

a_{x} - Acceleration in +x direction, measured in meter per square second.

t - Time, measured in seconds.

v_{y} - Velocity in +y direction, measured in meters per second.

If we know that v_{o,x} = 0\,\frac{m}{s}, a_{x} = 0.250\,\frac{m}{s^{2}}, t = 45\,s and v_{y} = 21.4\,\frac{m}{s}, the final velocity of the satellite is:

\vec{v}_{S} = \left[0\,\frac{m}{s}+\left(0.250\,\frac{m}{s^{2}} \right)\cdot (45\,s) \right]\,\hat{i}+\left(21.4\,\frac{m}{s} \right)\,\hat{j}

\vec{v_{S}} = 11.25\,\hat{i}+21.4\,\hat{j}\,\,\left[\frac{m}{s} \right]

a) The magnitud of the satellite's velocity can be found by the resource of the Pythagorean Theorem:

\|\vec {v}_{S}\| = \sqrt{\left(11.25\,\frac{m}{s} \right)^{2}+\left(21.4\,\frac{m}{s} \right)^{2}}

\|\vec{v}_{S}\| \approx 24.177\,\frac{m}{s}

The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is determined with the help of trigonometric functions:

\tan \alpha = \frac{v_{y}}{v_{x}} = \frac{21.4\,\frac{m}{s} }{11.25\,\frac{m}{s} }

\tan \alpha = 1.902

\alpha = \tan^{-1}1.902

\alpha \approx 62.266^{\circ}

The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

4 0
3 years ago
On a hot summer day, you and your friends decide to have a picnic at the park. To keep your food fresh you pack your lunch in a
g100num [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The <u>Fruit juice </u> should be put in the cooler, because <u>it has the greatest heat capacity</u> and will therefore, <u>absorb the most heat for each degree it increases in temperature.</u>

Explanation:

in order to understand the answer above we need to know what specific heat capacity is

       Specific heat capacity  can be defined as the amount of heat required to raise the temperature of a unit mass of a substance by one degree  

     Looking at the specific heat of each substance suggested we see that the fruit juice has a higher specific heat capacity than others this is because it contains a higher amount of water , generally liquid states of substances have a higher specific heat capacity than other states. The specific heat capacity of fruit juice being the highest among the suggested substances means that it can absorb  more heat for each degree temperature of refrigerator.

8 0
4 years ago
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