The net force acting on the airplane is 25N.
Forces acting on the paper airplane when it is in the air:
- The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.
- Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.
- Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.
- Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.
Given.
Weight of the paper airplane, F1 = 16N
The force of air resistance, F2 = 9N
Net force = F1 + F2
Net force = 25N
Thus, the net force acting on the airplane is 25N.
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Answer:
- 1.42m/s²
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time.
Acceleration = change in velocity/time
Change in velocity = final velocity - initial velocity
Acceleration = final velocity - initial velocity/time
Since she slows her car from 14.0 to 5.5m/s in 6seconds,
Initial velocity = 14m/s
Final velocity = 5.5m/s
Time = 6seconds
Substituting in the given formula, we will have
Acceleration = 5.5 - 14/6
Acceleration = - 8.5/6
Acceleration = - 1.42m/s²
The negative acceleration shows that the car decelerates.
To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function
Here,
m = mass
a = g = Gravitational acceleration
Replacing we have that the weight is
Since the rope is taut and does not break, the net force on the rope will be zero.
Therefore the tensile force in the rope is 98N
Answer:
p=mv=(813kg)(17)= 13,821 kg m\s
