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ira [324]
3 years ago
11

A car is traveling at 20 m/s. It takes the car 120s to go from one intersection to a second. What was the displacement of the ca

r between the two intersections?
Physics
1 answer:
Bad White [126]3 years ago
7 0

We don't know if the road is perfectly straight between the intersections,  or if the road bends, curves, or turns between them.  So we don't have enough information to calculate the displacement between them.

But we <em>can</em> calculate the <u>distance</u> the car traveled between them.

Distance = (speed) (time)

Distance = (20 m/s) (120 s)

<em>Distance = 2,400 meters</em>

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Answer:

F=43570.9N

Explanation:

We can calculate the acceleration experimented by the passenger using the formula v_f^2=v_i^2+2ad, taking the initial direction of movement as the positive direction and considering it comes to a rest:

a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

F=ma=\frac{-mv_i^2}{2d}

Which for our values is:

F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N

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