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ExtremeBDS [4]
4 years ago
14

Neglecting air resistance, when does a struck baseball accelerate downward at a rate of 9.8 m/s2?

Physics
2 answers:
olga2289 [7]4 years ago
3 0
A baseball is accelerated downward at 9.8 m/s^2 when the only vertical force acting upon the baseball is gravity.
creativ13 [48]4 years ago
3 0

Answer:

Only at the precise moment when it has reached maximum height.

Explanation:

It's the precise moment when it accelerates downward.

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The energy of a sound wave relates to its
snow_lady [41]
The answer is B. , it will relates to its amplitude

Amplitude is the maximum extent of a vibration  or oscilation , measured from the position of equilibrium.

Hope this help you out
6 0
3 years ago
Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!
Ainat [17]

The total electrostatic force on charge A is 28 \mu N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

x_A = 0\\x_B = 10 m\\x_C = 20 m

The magnitudes of the three charges are:

q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
4 years ago
The greater the difference in electronegativity between two covalently bonded<br><br> atoms
katrin [286]

Answer:

The greater the difference in electronegativity between two covalently bonded atoms, the greater the bond's percentage of ionic character.

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Bond polarity (i.e the separation of electric charge along a bond) and ionic character (amount of electron sharing) increase with an increasing difference in electronegativity.

Therefore, we can say that, the greater the difference in electronegativity between two covalently bonded atoms, the greater the bond's percentage of ionic character.

7 0
3 years ago
A heat engine uses thermal energy that flows from a heat source with a temperature of 325 K to a cold sink, which has a temperat
Ilya [14]
The answer is "58.5"
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The snail was going at 0.5

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