If current is passed through two parallel conductors in the same direction and the conductors are placed near each other, they will attract each other.
<h3>What is electric current?</h3>
Electric current can be defined as the flow of electrons.
Since electrons are easily removed from atom and are very mobile, the flow of electrons constitute an electric current.
Materials which allow electric current to flow through them are known as conductors. Examples of conductors are metals, and electrolytes.
On the other hand, materials which do not allow electric current to pass through them are known as insulators. Examples of insulators are wood and rubber.
The flow of current is known as electricity.
Parallel conductors with current flowing through them in the same direction are attracted to each other as a result of a magnetic field produced by the flow of current.
In conclusion, conductors allow electric current to pass through and the flow of current through a conductor produces a magnetic field.
Learn more about parallel conductors at: brainly.com/question/17148082
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Answer:
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<h2><u><em>
D</em></u></h2>
Explanation:
3) For a displacement time graph, straight line denotes constant speed. For a velocity time graph, the graph parallel to time axis denotes constant speed. Hence, the correct option is a) and d).
Answer:
2943 J
Explanation:
Potential energy = mass x acceleration due to gravity x height in meters
(P.E. = mgh)
Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)
PE = 40 x 9.81 x (0.15x50)
PE = 2943 J
Answer:
The current in the second loop will stay constant
Explanation:
Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)
Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.
So, i₂R = -Mdi₁/dt
i₂ = -Mdi₁/dt/R
Since di₁/dt = + 1 A/s,
i₂ = -Mdi₁/dt/R
i₂ = -M × + 1 A/s/R
i₂ = -M/R
Since M and R are constant, this implies that i₂ = constant
<u>So, the current in the second wire loop will stay constant.</u>
