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tangare [24]
2 years ago
15

Tristan is an engineer working on a design for a new roller coaster. He wants the car to shoot out of the station very fast but

needs a superconductor to be able to accomplish this. He is looking at different materials to use on the tracks of the roller coaster. What is necessary for his material to function as a superconductor? Check all that apply. ОТ< То a solid metal conductivity a very cold temperature a low boiling point no resistance
​
Physics
1 answer:
uysha [10]2 years ago
7 0

Answer:

Superconducting materials can transport electrons with no resistance, and hence release no heat, sound, or other energy forms. Superconductivity occurs at a specific material's critical temperature (Tc). As temperature decreases, a superconducting material's resistance gradually decreases until it reaches critical temperature. At this point resistance drops off, often to zero, as shown in the graph at right.

Explanation:

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2 years ago
Suppose you are standing on the edge of a dock and jump straight down. If you land on sand your stopping time is much shorter th
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Answer:

In bringing you to a halt, the sand and the water exert the same impulse on you, but the sand exerts a greater average force

Explanation:

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3 years ago
A police officer at rest at side of highway notices speeder moving at 62 km/h along road.when speeder passes ,officer accelerate
Korolek [52]

To answer the following questions for this specific problem:

a. 11.48 secs

b. Vp = a*t*3.6 = 3*11.48*3.6 = 124.0 km/h

<span>c. 9.1 secs. </span>

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4 0
3 years ago
Read 2 more answers
The Faraday disk was an early example of what?
Evgen [1.6K]
Electrical generator which operates using a magnetic field. It is the beginning of modern dynamos.
8 0
3 years ago
0/2 File Limit
slamgirl [31]

Answer:

Speed at which it will reach the ground is given as

v_f = 46.8 m/s

Total time for which it will remain in air is given as

t = 6.3 s

Explanation:

As we know that the object is projected upwards with speed

v_i = 15 m/s

g = - 9.81 m/s^2

now when it will reach the ground then we have

y = v_y t + \frac{1}{2} at^2

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4.905 t^2 - 15 t - 100 = 0

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v_f = 46.8 m/s

8 0
3 years ago
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