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Aleks [24]
3 years ago
5

A marble is selected at random from a jar containing 5 red marbles, 2 yellow marbles & 3 green marbles. What is the probabil

ity that a)the marble is red
b)the marble is not yellow
c)the marble is either red or green
d)the marble is neither red nor green
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

5/11

explanation

Probability here is the chance of selection out of a total. So, we need to first find the total number of marbles.

total

=

5

+

3

+

2

+

1

=

11

So there are  

11

marbles total. The probability that we pick one of the  

3

green marbles out of the  

11

is simply that ratio:

P

green

=

3

11

Same idea for yellow:

P

yellow

=

2

11

The probability of picking either of these colors is simply the sum of their probabilities.

P

green or yellow

=

P

green

+

P

yellow

=

3

11

+

2

11

=

5

11

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what is the surface area of a rectangular prisim with a base length of 9 yd, base width of 7 yd,and a height of 4 yd?
krek1111 [17]

Answer:

254 yds²

Step-by-step explanation:

There are 6 faces of the prism we need to calculate the area of for a rectangular prism.

The base and top of the prism measure 9x7 yards each, so there are two faces with an area of 63 yds²                 (9 x 7 = 63)

The sides of the prism measure 4x7 yards each, so there are two faces with an area of 28 yds²    (4 x 7 = 28)

The front and back face of the prism measure 9x4 yards each, so there are two faces with an area of 36 yds²     (9 x 4 = 36)

The total surface area is

2(63) + 2(28) + 2(36) = 254 yds²

3 0
3 years ago
Read 2 more answers
What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

\sqrt{11}  -  \sqrt{3}

which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

\frac{5( \sqrt{11}  +  \sqrt{3} )}{11   -  3}

This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

\frac{5 }  {8}\sqrt{11}  + \frac{5 }  {8}\sqrt{3}

8 0
3 years ago
Read 2 more answers
what is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 3/4?
Troyanec [42]
Y = mx + b
slope(m) = 3/4
(5,-4)...x = 5 and y = -4
now we sub
-4 = 3/4(5) + b
-4 = 15/4 + b
-4 - 15/4 = b
-16/4 - 15/4 = b
- 31/4 = b....or - 7 3/4 = b

so ur equation is : y = 3/4x + (-31/4) or y = 3/4x - 31/4
3 0
3 years ago
1. Calculati! ( Va rog ajutati-ma! )
Ksju [112]
1. 7+ (-9) = 7-9=-2
2.(-8) + (+5)= -8+5= -(8-5)=-3
3.(+9) - (-3) = 9+3=12
4.(+12) - (-1) = 12+1=13
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<span>(-14) - (+2) = -14-2=-(14+2)=-16</span>
8 0
3 years ago
Name the line of reflection used to map each preimage to its image
rewona [7]

Answer:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

   Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' →  → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

    Coordinates of G' → (-2, 5)

    Midpoint joining the segment GG' →  → (0, 5)

    Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

    y = -x

Step-by-step explanation:

3 0
2 years ago
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