Answer: nutrients
Explanation: to help the cells have energy
Answer:
0.5°c
Explanation:
Humidity ratio by mass can be expressed as
the ratio between the actual mass of water vapor present in moist air - to the mass of the dry air
Humidity ratio is normally expressed in kilograms (or pounds) of water vapor per kilogram (or pound) of dry air.
Humidity ratio expressed by mass:
x = mw / ma (1)
where
x = humidity ratio (kgwater/kgdry_air, lbwater/lbdry_air)
mw = mass of water vapor (kg, lb)
ma = mass of dry air (kg, lb)
It can be as:
x = 0.005 (100) / [(100 - 100)]
x = 0.005 x 100 / (100 - 100)
x = 0.005 x 100 / 0
x = 0.5°c
So the temperature to which atmospheric air must be cooled in order to have humidity ratio of 0.005 lb/lb is 0.5°c
Answer:
1) titration
2) titrand
3) equivalence point
4) titrant
5) Burette
6) Indicator
Explanation:
The process in which a known volume of a standard solution is added to another solution so that the standard solution can react with the solution of unknown concentration such that its concentration is determined can be referred to as titration.
The solution which is added to another solution is called the titrant. The titrand is the solution of unknown concentration
A burette is a glassware used to slowly add a known volume of the titrant to the titrand.
The indicator used signals the point when the reaction is complete by a color change. At this point, a stoichiometric amount of titrant has been added to the titrand. This is also referred to as the equivalence point.
The load is 17156 N.
<u>Explanation:</u>
First compute the flexural strength from:
σ = FL / π![R^{3}](https://tex.z-dn.net/?f=R%5E%7B3%7D)
= 3000
(40
10^-3) / π (5
10^-3)^3
σ = 305
10^6 N / m^2.
We can now determine the load using:
F = 2σd^3 / 3L
= 2(305
10^6) (15
10^-3)^3 / 3(40
10^-3)
F = 17156 N.
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81
· 1.50m
= 35.316 ![\frac{N}{m}](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7Bm%7D)
= 35.316 W