The magnitude of shear stress (kPa) on an element a lying at a distance of 20 mm from neutral axis. (6 pts) are given, p = 2kn e = 210gpa distance from constant cease = 20mm = 0.2m.
<h3>What is the cantilever formula?</h3>
The cantilever beam equations (deflection) w = load. l = member length. e = young's modulus. i = the beam's moment of inertia.
- theta= 2000 2*210*10^ 9 * (0.006)^ four 12 [(0.1)^ 2 -(0.08)^ 2 ] =0.1587 rad
- ø at q i.e. x = 100 - 20 = 80mm = 0.08m from loose cease.
- theta = p/(2ei) * (l ^ 2 - x ^ 2) phase of facet a. i = (a ^ four)/12 for square.
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The field of strength of materials, also called mechanics of materials, typically refers to various methods of calculating the stresses and strains in structural members, such as beams, columns, and shafts. The methods employed to predict the response of a structure under loading and its susceptibility to various failure modes takes into account the properties of the materials such as its yield strength, ultimate strength, Young's modulus, and Poisson's ratio. In addition, the mechanical element's macroscopic properties (geometric properties) such as its length, width, thickness, boundary constraints and abrupt changes in geometry such as holes are considered.
The theory began with the consideration of the behavior of one and two dimensional members of structures, whose states of stress can be approximated as two dimensional, and was then generalized to three dimensions to develop a more complete theory of the elastic and plastic behavior of materials. An important founding pioneer in mechanics of materials was
Answer:
Explanation:
Given
diameter(d)=1.1 m
mean velocity(u)=50 cm/s
mass flow rate(m)=110 kg/s
where
=density of fluid
Therefore specific gravity
Specific weight
specific volume
Explanation:
Shut the air condioner and blower motor off and wait for the refrigerant to accumulate. ... After a system has been opened for repair, the system should be properly leak tested before charging with refrigerant. The system should hold a deep vacuum (27 in HG. or more) for at least one minute before charging.
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Federal Clean Air Act Section 609 Training Manual ... - ESCO Institute
Answer:
total width bandwidth = 8kHz
Explanation:
given data
transmitter operating = 3.9 MHz
frequencies up to = 4 kHz
solution
we get here upper side frequencies that is
upper side frequencies = 3.9 ×
+ 4 × 10³
upper side frequencies = 3.904 MHz
and
now we get lower side frequencies that is
lower side frequencies = 3.9 ×
- 4 × 10³
lower side frequencies = 3.896 MHz
and now we get total width bandwidth
total width bandwidth = upper side frequencies - lower side frequencies
total width bandwidth = 8kHz