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Anarel [89]
3 years ago
9

Chlorine has two isotopes. The isotope with a mass of 34.969 amu has a relative abundance of 75.77%. The isotope with a mass of

36.966 amu has a relative abundance of 24.33%. Calculate the atomic mass of chlorine. Please show how you got answer. lots of points. big money$$$$$$$$
Chemistry
2 answers:
Mars2501 [29]3 years ago
5 0
34.969*.7577+36.966*.2433=35.489
Viefleur [7K]3 years ago
5 0
(34.969*0.7577)+(36.966*0.2433) = the atomic mass of chlorine.

Input into a calculator and your answer is: 35.4898 AMU (atomic mass units)


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Identify the mixture of gasoline and motor oil and suggest a technique for separating their components. 1. homogeneous; decantin
alexgriva [62]

Answer:

4. homogeneous; distillation

Explanation:

Gasoline and motor oil are chemically similar. They are both mixtures of non polar hydrocarbons containing carbon and hydrogen atoms. However, motor oil is much more viscous Motor Oil. Hence we can say that the mixture of gasoline and motor oil are homogeneous and they can be separated by distillation.

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Neutral atom contains 22 protons and 24 neutrons​
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How many molecules are in 6.0g of sodium phosphate?
Phantasy [73]

Answer:

2.2 x 10²² molecules.

Explanation:

  • Firstly, we need to calculate the no. of moles in (6.0 g) sodium phosphate:

<em>no. of moles = mass/molar mass </em>= (6.0 g)/(163.94 g/mol) = <em>0.0366 mol.</em>

  • <em>It is known that every mole of a molecule contains Avogadro's number (6.022 x 10²³) of molecules.</em>

<em />

<u><em>using cross multiplication:</em></u>

1.0 mole of sodium phosphate contains → 6.022 x 10²³ molecules.

0.0366 mole of sodium phosphate contains → ??? molecules.

<em>∴ The no. of molecules in  6.0 g of sodium phosphate</em> = (6.022 x 10²³ molecules)(0.0366 mole)/(1.0 mole) = <em>2.2 x 10²² molecules.</em>

3 0
3 years ago
What is the balanced equation for the reaction of a solution of sodium sulfate is mixed with strontium chloride?
natta225 [31]

Answer:

NaSO⁴(ads) ,ganadicate

6 0
3 years ago
Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

6 0
3 years ago
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