<h2>Answer : 1 is gamma, 2 is alpha and 3 is beta radiations.</h2><h3>Explanation :</h3>
In the given information all the radiations were stopped by the lead block, if we assume that first radiations were gamma radiation, as they were not stopped by the cloth whereas all other radiations were stopped.
In second case, aluminum foil and wood were able to block alpha and beta radiations. Whereas, paper was used to stop the alpha particles but not the gamma and beta rays. And then a thick concrete stopped all the radiations.
This clarifies that the first radiation are gamma rays, second is alpha rays and third is beta rays.
I’m not sure but one type of energy is light to heat this happens by the solar panels converting the power to heat for the oven. Another one is radiation to cook a bowl of soup there has to be radiation. Last one I’m not sure but I hope you understand. Hope this also helps too. I send in the comments if I figure it out.
It is true because protons are positively charged and electrons are negatively charged. if there is the same number of protons and electrons, both charges cancel out.
Answer:
Your question is not complete, but use this answer as a guide for your solution.
Question: A chemistry student weighs out 0.112g of acetic acid (HCH₃CO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1600 <em>M</em> NaOH solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.
Answer: Volume of NaOH is 11.6 mL
Explanation:
The reaction of acetic acid with NaOH is as follows:
CH3COOH + NaOH -----> CH3COONa + H2O
M1V1 = M2V2
Here M1 V1 are molarity and volume of acetic acid.
M2, V2 are molarity and volume of NaOH.
Number of moles of acetic acid:
0.112 g CH3COOH × (1 mol / 60.05 g) = 0.001865 mol
Molarity = moles of solute / Liters of solution
Molarity = 0.001865 mol / 0.250 L = 0.00746 M
Hence,
M1 = 0.00746 M
V1 = 250 mL
M2 = 0.160 M
V2 = ?
V2 = M1V1 / M2
V2 = 0.00746 M × 250 mL / 0.160 M
V2 = 11.6 mL
Hence the volume of NaOH is 11.6 mL