2 more than the product of 2 and x

Find three ratios equivalent to the given ratio 8/10 5/2

valkas [14]

For 8/10:
16/20
24/30
64/80

for 5/2:
10/4
20/8
100/40

hope this helps

7 0

3 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago

A person is trapped in a burning building 60feet off the ground. A rescuer has a 70 foot ladder, but for safety purposes the lad

Neko [114]

Yes because, if the building is 60 ft from the ground and the ladder is 70 ft,shouldn’t it escalate an extra 10 ft because this is technically an emergency and it can be considered to be used as a reason for safety purposes, if I’m not mistaken

3 0

3 years ago

The spring concert at a certain high school sold 155 tickets. Students were charged $4 each and adults $8 each. The income from

garik1379 [7]

Answer:

Step-by-step explanation: 85 students and 80 adults

6 0

3 years ago

The second side of a triangular deck is 4 feet longer than the shortest side, and the third side is 4 feet shorter than twice th

xxTIMURxx [149]

We don’t know the value of the shorter side, so we will categorize it as x. Side 2 is just 4 feet longer than x, so we would add 4 on to it. Side 3 has double the x, so we would multiply it be 2 for 2x, and subtract the 4 feet from it.

Side 1: x
Side 2: x + 4
Side 3: 2x - 4

If the perimeter is 64 feet, then all of the sides have to add up to it. Therefore, first we add all of the side lengths up:

x + x + 4 + 2x - 4 = 4x.

Now we put 4x, the amount of all these sides added up, equal to the perimeter of 64.

4x = 64. Divide both sides by 4 to get x by itself.
x = 16.

Now that we know x is 16, we will substitute it in for all the side lengths’ equations.

We know that Side 1 was just x, so that will be 16. Since Side 2 was 4 more than x, we’d do 16 + 4 = 20. We substitute 16 in for x in Side 3’s equation: 2(16) - 4 = 32 - 4 = 28.

Therefore, the final lengths of all the sides are:

Side 1: 16
Side 2: 20
Side 3: 28

5 0

3 years ago