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rosijanka [135]
3 years ago
9

Why doesn't water light on fire? It has all the ingredients except heat! Hydrogen for the flammability factor, oxygen so it can

keep burning, and all you need to do is add heat and BOOM you have a flame! 15 pts
Chemistry
2 answers:
Fiesta28 [93]3 years ago
6 0

Hydrogen- and Oxygen Atoms combine to form a whole net molecule called H20 (Water), which has completely different properties and pure water can't ignite

Svetach [21]3 years ago
6 0

Answer:well because water is moiste ugh XD not that word ok ill be serious becaus its water sorry idk im only in 6th grade

Explanation:

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Calculating the expected pH of the buffer solution: Given that the pKa for Acetic Acid is 4.77, calculate the expected pH of the
ser-zykov [4K]

Answer:

pH=4.77

Explanation:

From the question we are told that:

pKa for Acetic Acid pK_a= 4.77

Therefore

For Equal Concentration of acetic acid and acetatic ion

CH_3COOH=CH_3COO^-

Generally the Henderson's equation for pH value is mathematically given by

pH=pK_a+log\frac{base}{acid}

pH=4.77+log\frac{CH_3COO^-}{CH_3COOH}

pH=4.77+log1

pH=4.77

5 0
3 years ago
The type of bonding and the numbers of covalent bonds an atom can form with other atoms are determined by __________. View Avail
Dmitriy789 [7]

Answer:

The answer is: the number of unpaired valence electrons

Explanation:

The valence electrons are the number of electrons present in outer shell of an atom that participate in chemical bond formation, if the outer shell is not completely filled.

Covalent bond formation occurs when two atoms contribute one valence electron each to form a bond. Thus the number of covalent bonds that an element can form, can be determined by the number of unpaired valence electrons.

Therefore, the nature and the number of bonds formed by the element and the chemical properties of the element can be determined by the number of valence electrons present in the outer shell of the element.

4 0
3 years ago
What is the percentage of sodium presents in sodium hydrogen carbonate NaHCO3
STatiana [176]

Answer:-

27.38%

Explanation:-

Molecular weight of sodium hydrogen carbonate NaHCO3

= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3

= 84 gram

Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram

Percentage of sodium present=

Total sodium x 100/ (Total molecular weight)

= 23 x 100 / 84

= 27.38 %

3 0
3 years ago
What is the molar mass of Ni(SiO3)3
Vsevolod [243]
The molar mass is 286.94 g/mol
7 0
3 years ago
Read 2 more answers
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
3 years ago
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