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timofeeve [1]
3 years ago
13

What is the molecular formula of eggs?

Chemistry
1 answer:
Naya [18.7K]3 years ago
5 0
C37H70NaO8P is the molecular formula for an egg
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What mass of copper is required to replace silver from 4.00g of silver nitrate dissolved in water?
larisa [96]
The balanced chemical reaction is written as:

<span>Cu +2AgNO3 → Cu(NO3)2 + 2Ag
</span>
We are given the amount of silver nitrate to be used for the reaction. This value will be the starting point of our calculations. It is as follows:

4.00 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Cu / 2 mol AgNO3 ) ( 63.456 g / 1 mol ) = 0.747 g Cu
3 0
3 years ago
What is the difference between the number of electrons in an atom of selenium?
azamat

Explanation:

Supposing we have to find the difference between the number of electrons in Selenium and Aluminium.

Well, electrons can be transformed to an atomic number, so if SE is 34, that means it has 34 electrons. AI has an atomic number of 13, which means it has 13 electrons. So the difference is that more electrons than AI are available from SE.

3 0
3 years ago
What is the mass of 2 moles of nitrogen gas, N2?
drek231 [11]

Answer:

28g

Solution. Hence, 2 moles of nitrogen atoms weigh 28g.

6 0
3 years ago
Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value.
frez [133]
The correct response is the second option.
6.1103x10^4. As this was the only answer that had the same number of significant figures as the starting value.
6 0
3 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
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