Answer:
Part A. The half-cell B is the cathode and the half-cell A is the anode
Part B. 0.017V
Explanation:
Part A
The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).
So, the half-cell B is the cathode and the half-cell A is the anode.
Part B
By the Nersnt equation:
E°cell = E° - (0.0592/n)*log[anode]/[cathode]
Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.
E°cell = 0 - (0.0592/2)*log(0.23/0.87)
E°cell = 0.017V
Hydrogen, helium and oxygen
Answer: Explanation:
Temperatura. La solubilidad de un soluto en un determinado solvente principalmente depende de la temperatura. Para muchos sólidos disueltos en el agua líquida, la solubilidad aumenta con la temperatura hasta 100 °C, aunque existen casos que presentan un comportamiento inverso.
<em>the </em><em>new </em><em>volume </em><em>will </em><em>be </em><em>8</em><em>2</em><em>×</em><em>1</em><em>0</em><em>-</em><em>3</em><em> </em><em>L </em><em>or </em><em>0</em><em>.</em><em>0</em><em>0</em><em>8</em><em>2</em><em> </em><em>L</em>
Volume is directly proportional to the number of moles
