3:5.....added = 8
3/8(40) = 120/8 = 15 m <== one piece
5/8(40) = 200/8 = 25 m <== the other piece
T=26
you just add 7 to the other side with 19 which gives you the answer
I believe the answer is 1 because the line is negative and has a slope of 1/2 so -1/2 and it crosses at 8
Area is equal to length times width. The perimeter (the amount of rope) has to equal twice the length added to twice the width so we're left with:
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2
