All categories

2 years ago

Please help with geometry problems

Mathematics

1 answer:

sertanlavr [38]2 years ago

6 0

Answer:

put your best gees

Step-by-step explanation:

You might be interested in

In a ten pin bowling the highest possible score in a single game is 300. At one point in the season, John had an average score o

Sindrei [870]

Answer:

John need to get 293 in his next game to bring his average up to 183.

Step-by-step explanation:

John starts with N games played and averaging 177 points per game.

In game N+1, John scored 199 points.

$\frac{177N + 199}{N+1}=178\\177N+199=178N+178\\N=21\\$

So, John has now played (N+1) = 22 games.

We need to know what score John needs in game 23 to bring his average to 183.

$\frac{177*21 + 199+Y}{23}=183\\3916+Y=4209\\Y=293\\$

8 0

2 years ago

The perimeter of a geometric figure is the sum of the lengths of its sides. If the perimeter of the pentagon to the right (five-

Yuri [45]

2.5 divided by 2 equals 1.25 so each side equals 1.25

5 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

How do you know if the question is asking for you to do Pythagoras or Trigonometry? Like in basic terms, what’s the difference??

mrs_skeptik [129]

Pythagoras theorem only works for right triangle (90 degree)

Trigonometry (sin, cos, tan) works everywhere!

Hopefully I answered your question!

If you want to learn more about Trigonometry or Pythagoras theorem, send me a message and add me as friend on Brainly. I'm a mathematician and an astrophysicist

:) have a great day!

7 0

3 years ago

Hey there! This is my last math question of the day! Please, do me a favor and help me out! Please remember I need an inequality

Mars2501 [29]

Answer:

150 ≥ 55+0.20t

6 0

3 years ago