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frosja888 [35]
4 years ago
6

Explain why the total amount of energy does not decrease in an exergonic chemical reaction

Chemistry
1 answer:
Zielflug [23.3K]4 years ago
4 0

An exergonic reaction is a chemical reaction where the change in the free energy is negative (there is a net release of free energy),[1] indicating a spontaneous reaction. For processes that take place under constant pressure and temperature conditions, the Gibbs free energy is used whereas the Helmholtz energy is used for processes that take place under constant volume and temperature conditions.

Symbolically, the release of free energy, G, in an exergonic reaction (at constant pressure and temperature) is denoted as

{\displaystyle \Delta G=G_{\rm {products}}-G_{\rm {reactants}}<0.\,}

Although exergonic reactions are said to occur spontaneously, this does not imply that the reaction will take place at an observable rate. For instance, the disproportionation of hydrogen peroxide is very slow in the absence of a suitable catalyst. It has been suggested that eager would be a more intuitive term in this context.[2]

More generally, the terms exergonic and endergonic relate to the free energy change in any process, not just chemical reactions. An example of an exergonic reaction is cellular respiration. This relates to the degrees of freedom as a consequence of entropy, the temperature, and the difference in heat released or absorbed.

By contrast, the terms exothermic and endothermic relate to the overall exchange of heat during a process

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The correct answer is 57.5 L

Explanation:

According to the Charles's Law, as the temperature of a gas increases at constant pressure, its volume increases (the gas is expanded when it is heated). The mathematical expresion for two conditions (1 and 2) of a gas is the following:

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

Where V₁ and V₂ are the volumes of the gas in two different conditions (1 and 2); T₁ and T₂ are the temperatures in Kelvin of the gas in the two conditions 1 and 2.

In this case, V₁= 46.0 L and T₁= 400 K. Then, we heat the gas until it reaches T₂=500 K. In order to calculate the new volume (V₂), we introduce the data in the mathematical expression:

V₂= \frac{V_{1} }{T_{1} } x T₂

V₂= (46.0 L/ 400 K) x 500 K

V₂= 57.5 L

We corroborate our answer is coherent because 57.5 L > 46.0 L as we know that the volume increases with the increase of temperature (from 400 K to 500 K).

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