Answer: sorry i dont knowExplanation:
Answer:
1. 0.125 mole
2. 42.5 g
3. 0.61 mole
Explanation:
1. Determination of the number of mole of NaOH.
Mass of NaOH = 5 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass /molar mass
Mole of NaOH = 5/40
Mole NaOH = 0.125 mole
2. Determination of the mass of NH₃.
Mole of NH₃ = 2.5 moles
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 2.5 × 17
Mass of NH₃ = 42.5 g
3. Determination of the number of mole of Ca(NO₃)₂.
Mass of Ca(NO₃)₂ = 100 g
Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]
= 40 + 2[14 + 48]
= 40 + 2[62]
= 40 + 124
= 164 g/mol
Mole of Ca(NO₃)₂ =?
Mole = mass /molar mass
Mole of Ca(NO₃)₂ = 100 / 164
Mole of Ca(NO₃)₂ = 0.61 mole
Answer:
0.492 lb/in^3
Explanation:
From Density of Mercury (13.6g/cm3) given,
Mass = 13.6g
Volume = 1cm3
Now we covert these variables as follows :
For Mass:
454 g = 1 lb
13.6g = 13.6/454 = 0.03lb
For volume:
2.54 cm = 1 in
1cm = 1/2.54 = 0.394in
Volume = (0.394in)^3 = 0.061 in^3
Density = Mass /volume
Density = 0.03lb/0.061 in^3
Density = 0.492 lb/in^3
