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Yuliya22 [10]
3 years ago
9

2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)

Chemistry
1 answer:
Ket [755]3 years ago
5 0

Answer:- 10 L of ethane.

Solution:- The given balanced equation is:

2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.

Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:

14LO_2(\frac{2LC_2H_6}{7LO_2})

= 4LC_2H_6

From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L

Hence, 10 L of ethane will be remaining.

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<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

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