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GarryVolchara [31]
3 years ago
9

Consider steady heat transfer through the wall of a room in winter. The convection heat transfer coefficient at the outer surfac

e of the wall is three times that of the inner surface as a result of the winds. Hence, at the inner surface, the temperature will be closer to the surrounding air temperature. Explain.
Engineering
1 answer:
AveGali [126]3 years ago
6 0

The heat transfer which is in steady state, the heat transfer rate to the wall is equal to the wall.

<u>Explanation:</u>

  • The convection transfer of heat to the wall is

         Q=h A\left(T_{s}-T_{f}\right)

  • Here, T_{S} is the temperature of solid surface, T_{f} is the temperature of moving fluid stream which is adjacent of solid surface, h is the heat transfer coefficient.
  • The coefficient of convection heat transfers outer surface contains 3 times to the inner surface which experience smaller drop of temperature for 3 times that compares to inner surface.
  • Hence, the temperatures outer surface get close to the surroundings of air temperature.
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Air at a pressure of 6000 N/m^2 and a temperature of 300C flows with a velocity of 10 m/sec over a flat plate of length 0.5 m. E
White raven [17]

Answer:

Q=hA(T_{w}-T_{inf})=16.97*0.5(27-300)=-2316.4J

Explanation:

To solve this problem we use the expression for the temperature film

T_{f}=\frac{T_{\inf}+T_{w}}{2}=\frac{300+27}{2}=163.5

Then, we have to compute the Reynolds number

Re=\frac{uL}{v}=\frac{10\frac{m}{s}*0.5m}{16.96*10^{-6}\rfac{m^{2}}{s}}=2.94*10^{5}

Re<5*10^{5}, hence, this case if about a laminar flow.

Then, we compute the Nusselt number

Nu_{x}=0.332(Re)^{\frac{1}{2}}(Pr)^{\frac{1}{3}}=0.332(2.94*10^{5})^{\frac{1}{2}}(0.699)^{\frac{1}{3}}=159.77

but we also now that

Nu_{x}=\frac{h_{x}L}{k}\\h_{x}=\frac{Nu_{x}k}{L}=\frac{159.77*26.56*10^{-3}}{0.5}=8.48\\

but the average heat transfer coefficient is h=2hx

h=2(8.48)=16.97W/m^{2}K

Finally we have that the heat transfer is

Q=hA(T_{w}-T_{inf})=16.97*0.5(27-300)=-2316.4J

In this solution we took values for water properties of

v=16.96*10^{-6}m^{2}s

Pr=0.699

k=26.56*10^{-3}W/mK

A=1*0.5m^{2}

I hope this is useful for you

regards

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3 years ago
Tin atoms are introduced into an FCC copper ,producing an alloy with a lattice parameter of 4.7589×10-8cm and a density of 8.772
slega [8]

Answer:

atomic percentage = 143 %

Explanation:

Let  x be the number of tin atoms and there are 4 atoms / cell in the FCC structure , then 4 -x  be the number of copper atoms . Therefore, the value of x can be determined by using the density equation as shown below:

\mathbf{density (\rho) = \dfrac{(no \ of \ atoms/cell)(atomic \ mass )}{(lattice \ parameter )^3(6.022*10^{23} atoms/ mol)} }

where;

the lattice parameter is given as : 4.7589 × 10⁻⁸ cm

The atomic mass of tin is 118.69 g/mol

The atomic mass of copper is 63.54 g/mol

The density is 8.772 g/cm³

\mathbf{8.772 g/cm^3 = \dfrac{(x)(118.69 \ g/mol) +(4-x)(63.54 \ g/mol)}{(4.7589*10^{-8} cm )^3(6.022*10^{23} atoms/ mol)} }

569.32 = 118.69x + 254.16-63.54x

569.32 - 254.16 = 118.69x - 63.54 x

315.16 = 55.15x

x = 315.16/55.15

x = 5.72 atoms/cell

As there are four atoms per cell in FCC structure for the metal, thus, the atomic percentage of the tin is  calculated as follows :

atomic % = \frac{no \ of \ atoms \ per  \ cell \ in \ tin }{no \ of \ atoms \ per  \ cell \ in \ the \ metal}*100

atomic % = \frac{5.72 \ atoms / cell}{4 \ atoms/ cell} *100

atomic % = 143 %

7 0
3 years ago
In 1828, the diameter of the U.S. dime was changed to approximately 18 mm. What is this diameter when expressed in micrometers
neonofarm [45]

The diameter of an 18 mm dine when expressed in micrometers is; 18000 micrometers

<h3>Conversion of Units</h3>

We are given the diameter of dime at 18 mm.

Now, from conversion of units between mm(millimeter) and micrometer, we know that;

1 millimeter = 1000 micrometer.

Thus, by proportion, 18 millimeter will be;

18 millimeters × 1000 micrometers/1 millimeter

>> 18000 micrometers

In conclusion, the diameter of the 18mm fine in micrometers is; 18000 micrometers

Read more about conversion of units at; brainly.com/question/8421470

7 0
2 years ago
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