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Andrej [43]
3 years ago
11

Internal service quality means that an entire organization,

Engineering
1 answer:
svetoff [14.1K]3 years ago
7 0
True

Internal service are base on customer needs.

The customers are the priority
You might be interested in
3.24 Program: Drawing a half arrow (Java) This program outputs a downwards facing arrow composed of a rectangle and a right tria
Lostsunrise [7]

Answer:

Here is the JAVA program:

import java.util.Scanner; // to get input from user

public class DrawHalfArrow{ // start of the class half arrow

public static void main(String[] args) { // starts of main() function body

    Scanner scnr = new Scanner(System.in); //reads input

int arrowBaseHeight = 0; // stores the height of arrow base

int arrowBaseWidth  = 0; // holds width of arrow base

int arrowHeadWidth = 0; // contains the width of arrow head

// prompts the user to enter arrow base height, width and arrow head width

System.out.println("Enter arrow base height: ");

arrowBaseHeight = scnr.nextInt(); // scans and reads the input as int

System.out.println("Enter arrow base width: ");

arrowBaseWidth = scnr.nextInt();

/* while loop to continue asking user for an arrow head width until the value entered is greater than the value of arrow base width */

while (arrowHeadWidth <= arrowBaseWidth) {

    System.out.println("Enter arrow head width: ");

    arrowHeadWidth = scnr.nextInt(); }

//start of the nested loop

//outer loop iterates a number of times equal to the height of the arrow base

 for (int i = 0; i < arrowBaseHeight; i++) {

//inner loop prints the stars asterisks

      for (int j = 0; j <arrowBaseWidth; j++) {

          System.out.print("*");        } //displays stars

          System.out.println();          }

//temporary variable to hold arrowhead width value

int k = arrowHeadWidth;

//outer loop to iterate no of times equal to the height of the arrow head

for (int i = 1; i <= arrowHeadWidth; i++)

{     for(int j = k; j > 0; j--)     {//inner loop to print stars

       System.out.print("*");    } //displays stars

   k = k - 1;

   System.out.println(); } } } // continues to add more asterisks for new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.

The loop is used to output an arrow base of height arrowBaseHeight. So point (1) is satisfied.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow. So (2) is satisfied.

A temporary variable k is used to hold the original value of arrowHeadWidth so that it keeps safe when modification is done.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head. So (3) is satisfied.

The value of temporary variable k is decreased by 1 so the next time it enters  the nested for loop it will be one asterisk lesser.

The screenshot of output is attached.

8 0
4 years ago
Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stre
velikii [3]

Complete Question

Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stress is applied along a [121] direction. If slip occurs on a (101) plane and in a [111]  direction, compute the stress at which the crystal yields if its critical resolved shear stress is 2.9 MPa.  

Answer:

The  stress is \sigma  =  10. 655 MPa

Explanation:

From the question we are told that

  The critical yield resolved shear stress is  \sigma  = 2.9Mpa

First we obtain the angle  \lambda between the slip direction [121] and  [111]

             \lambda = cos^{-1} [\frac{(u_1 u_2 + v_1 v_2 + w_1 w_2}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_2^2 + v_2^2 + w_2 ^2)} }  ]

Where u_1 ,u_2 ,v_1 , v_2 , w_1 , w_2 are the directional indices

             \lambda  =  cos ^-[ \frac{(1) (-1) + (2) (1) + (1) (1)}{\sqrt{((1)^2 +(2)^2 + (1)^2)}\sqrt{((-1)^2 + (1)^2 + (1)^2 ) }  } ]

                = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{3}  } ]

                 = 61.87^0

Next is to obtain the angle \O between the direction [121] and [101]

              \O = cos^{-1} [\frac{(u_1 u_3 + v_1 v_3 + w_1 w_3}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_3^2 + v_3^2 + w_3 ^2)} }  ]

 Substituting 1 for u_1 , 2 for  v_1 , 1 for w_1 , 1 for  u_2, 0 for  v_2, and 1 for  w_2

            \O = cos^{-1} [\frac{1* 1 + 2*0 + 1*1 }{\sqrt{1^2 + 2^2 + 1^2 } \sqrt{(1^2 + 0^2 + 1^2 )}  } ]

               \O = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{2}  } ]

                   = 54.74 ^o

   The stress is mathematically represented as

              \sigma = \frac{\tau_c}{cos \O cos \lambda }

                  = \frac{2.9}{cos 54.74^o cos 61.87^o}

                  =  \frac{2.9}{0.2722}

             \sigma  =  10. 655 MPa

           

       

5 0
3 years ago
A contractor is planning on including several skylights in each unit of a residential development. What type of worker would she
Sladkaya [172]

Answer:

Glazier

Explanation:

Glaziers are workers who specializes in cutting and installation of glass works.

They work with glass in various surfaces and settings, such as cutting and installing windows and doors, skylights, storefronts, display cases, mirrors, facades, interior walls, etc.

Thus, the type of worker the contractor will hire for this project is a Glazier

8 0
3 years ago
If you find yourself suddenly without headlights, slam on your brakes. A. TRUE B. FALSE
BigorU [14]
Should headlight failure happen suddenly, follow these steps. Don't stop suddenly, particularly if there is traffic near you. If you have no visibility, slow down and, at a very slow speed, move onto the slow shoulder. You should be moving slowly enough to avoid hitting anything.
5 0
3 years ago
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Anh/chị hãy trình bày cấu trúc hệ thống điều khiển ổn định điện áp. Hãy nêu các thành phần cơ bản chính trong hệ thống điều khiể
ryzh [129]

Answer:

do te ghjvbkiyrbkknbggvnjjhgcvnjjgvbbhh

3 0
3 years ago
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