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3 years ago

Multiply fractions is really hard for me because I hate fractions

Mathematics

1 answer:

earnstyle [38]3 years ago

4 0

It’s not that hard all u need to do is when u multiply it just multiply it. For example what’s 2/3x4/3=8/3 and that is just 8/3 but when the denominator is different u just multiply it it’s not that hard

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IT’S TIMED NEED HELP ASAP! If you don’t know please don’t answer

enot [183]

Answer:

12.2 or 12 2/9

Step-by-step explanation:

You set them equal to each other and solve

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4 years ago

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Find the inverse of g(x)=2x-3

AlexFokin [52]

=1/2x-3

Step-by-step explanation:

3 0

3 years ago

Help me with the work please if you can

timurjin [86]

Answer:

1/3

Step-by-step explanation:

48+32+16=96

numerator : 32

denominator : 96

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6 0

3 years ago

Solve this problem by using variation of parameters method.<br> y''-y=coshx.

Gekata [30.6K]

$y''-y=0\implies r^2-1=0\implies r=\pm1$
$\implies y_c=C_1e^x+C_2e^{-x}={C^*}_1\underbrace{\cosh x}_{y_1}+{C^*}_2\underbrace{\sinh x}_{y_2}$

For the nonhomogeneous ODE

$y''-y=\underbrace{\cosh x}_{f(x)}$

we're looking for a particular solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\int\frac{y_2(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx$
$u_2=\displaystyle\int\frac{y_1(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the two fundamental solutions.

We have

$W(y_1,y_2)=\begin{vmatrix}\cosh x&\sinh x\\\sinh x&\cosh x\end{vmatrix}=\cosh^2x-\sinh^2x=1$

so we're left with

$u_1=-\displaystyle\int\sinh x\cosh x\,\mathrm dx=-\dfrac12\cosh^2x$
$u_2=\displaystyle\int\cosh^2x\,\mathrm dx=\dfrac12x+\dfrac14\sinh2x$

so that the particular solution is

$y_p=-\dfrac12\cosh^3x+\dfrac12x\sinh x+\dfrac14\sinh x\sinh2x$
$y_p=-\dfrac12\cosh x+\dfrac12x\sinh x$

As $y_1$ already accounts for the $\cosh x$ term in $y_p$ , we're left with the general solution

$y=C_1\cosh x+C_2\sinh x+\dfrac12x\sinh x$

3 0

3 years ago

456 000 has been rounded to the nearest thousand. What was the smallest possible number this could have been?

Reika [66]

The smallest possible number could have been 455,500

3 0

3 years ago

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