For an Ohmic conductor, tripling the voltage without changing the resistance will cause the current to

What should you do with leftover prescription medication after you

stellarik [79]

Answer:PROPERLY DISCARD THE REMAINING PILLS

Explanation: IT COULD BE EXPIRE AND YOU NEED THEM ANY MORE DISPOSE THEM!!!!!!!!

8 0

4 years ago

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Identify and label the Brønsted-Lowry acid, its conjugate base, the Brønsted-Lowry base, and its conjugate acid in each of the f

julia-pushkina [17]

Explanation:

As per Brønsted-Lowry concept of acids and bases, chemical species which donate proton are called Brønsted-Lowry acids.

The chemical species which accept proton are called Brønsted-Lowry base.

(a) $HNO_3 + H_2O \rightarrow H_3O^+ + NO_3^-$

$HNO_3$ is Bronsted lowry acid and $NO_3^-$ is its conjugate base.

$H_2O$ is Bronsted lowry base and $H_3O^+$ is its conjugate acid.

(b)

$CN^- + H_2O \rightarrow HCN + OH^-$

$CN^-$ is Bronsted lowry base and HCN is its conjugate acid.

$H_2O$ is Bronsted lowry acid and $OH^-$ is its conjugate base.

(c)

$H_2SO_4 + Cl^- \rightarrow HCl + HSO_4^-$

$H_2SO_4$ is Bronsted lowry acid and $HSO_4^-$ is its conjugate base.

Cl^- is Bronsted lowry base and HCl is its conjugate acid.

(d)

$HSO_4^-+OH^- \rightarrow SO_4^{2-}+H_2O$

$HSO_4^-$ is Bronsted lowry acid and $SO_4^{2-}$ is its conjugate base.

OH^- is Bronsted lowry base and $H_2O$ is its conjugate acid.

(e)

$O_{2-}+H_2O \rightarrow 2OH^-$

$O_{2-}$ is Bronsted lowry base and OH- is its conjugate acid.

$H_2O$ is Bronsted lowry acid and OH- is its conjugate base.

6 0

4 years ago

According to Newton's First Law of Motion, what does it take to move an object at rest?

Rufina [12.5K]

I'm pretty sure the answer is B double check to make sure it isn't A

6 0

3 years ago

Which of these best represents the location of the Earth’s core?

djyliett [7]

Answer:

A

Explanation:

The pit of a peach. Simply, because this is the only answer that actually claims the core of the Earth isn't a type of outer shell.

7 0

3 years ago

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Assume that the complete combustion of one mole of glucose, a monosaccharide, to carbon dioxide and water liberates 2870 kJ2870

Lubov Fominskaja [6]

Answer:

number of moles of the compound $\approx$ 53 mole

Explanation:

Given that:

The total energy liberated = - 2870 kJ ( here , the negative sign typical implies the release of energy due to the combustion reaction)

The equation of the reaction can be represented as:

$\mathbf{C_6H_{12}O_6_{(s)} + 6O_{2(g)} \to 6CO_{2(g)}+6H_2O_{(l)}}$

The energy needed to synthesize 1 mole of compound X = - 54.1 kJ.mol

Thus;

The total energy = numbers of moles of compound × Energy needed to synthesize 1 mole of compound X

Making the numbers of moles of the compound the subject; we have;

numbers of moles of compound = $numbers \ of \ moles \ of \ compound = \dfrac{total \ energy }{Energy \ needed \ to \ synthesize \ 1 \ mole \ of \ compound \ X}$ $numbers \ of \ moles \ of \ compound = \dfrac{-2870 \ kJ }{-54.1 \ kJ/mol}$

number of moles of the compound = 53.04990 mole

number of moles of the compound $\approx$ 53 mole to two significant figure

7 0

3 years ago