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ArbitrLikvidat [17]
3 years ago
12

The number of protons in a neutral atom equals the number of

Physics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer: Electrons

Explanation: For a neutral atom the number of positively charged protons inside the nucleus must be equal to the number of electrons in the orbital shells. Both charges will cancel out having a charge of 0 which makes an atom electrically neutral.

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what is happiness

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A block of aluminum had a volume of 17.0 mL and a mass of 45.9g. What is it’s density?
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The density of aluminum is 2.7 g/ml.
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Sophia is planning on going down an 8-m high water slide. Her weight is 50 N. What is Sophia's Gravitational Potential Energy at
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As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o
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Answer:

18.6012339739 A

Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

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Magnetic field is given by

B=\dfrac{\mu_0NI}{L}\\\Rightarrow I=\dfrac{BL}{\mu_0N}\\\Rightarrow I=\dfrac{0.17\times 0.55}{4\pi \times 10^{-7}\times 4000}\\\Rightarrow I=18.6012339739\ A

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7 0
3 years ago
If the sprinter from the previous problem accelerates at that rate for 20 m, and then maintains that velocity for the remainder
kakasveta [241]

Question:

A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?

Answer:

Time for the race will be t = 9.26 s

Explanation:

Given data:

As the sprinter starts the race so initial velocity = v₁ = 0

Distance = s₁ = 20 m

Acceleration = a = 4.20 ms⁻²

Distance = s₂ = 100 m

We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.

Using 3rd equation of motion

(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)

v₂ = 12.96 ms⁻¹

Time for 20 m distance = t₁ = (v₂ - v ₁)/a

t₁ = 12.96/4.2 = 3.09 s

He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be

Time for 100 m distance = t₂ = s₂/v₂

t₂ = 80/12.96 = 6.17 s

Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s

T = 9.26 s

5 0
3 years ago
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