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Ymorist [56]
3 years ago
8

Miles and Allison are conducting a science experiment on bacteria and

Physics
2 answers:
andreyandreev [35.5K]3 years ago
4 0
I would answer with B..
maxonik [38]3 years ago
4 0
The answer would be b
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As the distance of a sound wave from its source quadruples, how is the intensity changed?
timurjin [86]
Through the 1/r law, it was concluded that for the sound intensity or pressure is directly proportional to distance or radius. That is,
                                 p = k/r 
where k is the proportionality constant. If the distance of a sound wave is quadrupled then, the intensity of the sound is decreased to 1/4 of its original value. 
8 0
3 years ago
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During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t^2 to s
Mila [183]

Answer:

70560 m

Explanation:

The formula to calculate the distance travelled during a free fall motion is

d=-\frac{1}{2}gt^2

where

d is the distance travelled

g = -9.8 m/s^2 is the acceleration due to gravity

t is the time

In this situation,

t = 120 s

Therefore the distance travelled after 120 s is

d=-\frac{1}{2}(-9.8)(120)^2=70560 m

6 0
4 years ago
- A cannon of 2000 kg fires a shell of 10 kg at
fgiga [73]

1) -0.5 m/s

We can solve the first part of the problem by using the law of conservation of momentum. In fact, the total momentum of the cannon - shell system must be conserved.

Before the shot, both the cannon and the shell are at rest, so the total momentum is zero:

p=0

After the shot, the momentum is:

p=MV+mv

where

M = 2000 kg is the mass of the cannon

m = 10 kg is the mass of the shell

v = 100 m/s is the velocity of the shell (we take as positive the direction of motion of the shell)

V = ? is the velocity of the cannon

Since momentum is conserved, we can write

0=MV+mv

And solving for V, we find the velocity of the cannon:

V=-\frac{mv}{M}=-\frac{(10)(100)}{2000}=-0.5 m/s

where the negative sign indicates that the cannon moves in the direction opposite to the shell.

2) 0.5 m

The motion of the cannon is a uniformly accelerated motion, so we can solve this part by using suvat equation:

v^2-u^2=2as

where

v is the final velocity of the cannon

u = 0.5 m/s is the initial velocity of the cannon (now we take as positive the initial direction of motion of the cannon)

a=-0.25 m/s^2 is the deceleration of the cannon

s is the distance travelled by the cannon

The cannon will stop when v = 0; substituting and solving the equation for s, we find the minimum safe distance required to stop the cannon:

s=\frac{v^2-u^2}{2a}=\frac{0-0.5^2}{2(-0.25)}=0.5 m

7 0
4 years ago
A block of cheese is pulled on by a string and slides to the right along a rough surface.
Ulleksa [173]

Answer:

Explanation:

KHAN ACADEMY

3 0
3 years ago
Which sediments typically make up the C horizon?
Nastasia [14]
B) sand, silt, and clay!
5 0
4 years ago
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