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andrew-mc [135]
3 years ago
11

Because Earth's rotation is gradually slowing, the length of each day increases: The day at the end of 1.0 century is 1.0 ms lon

ger than the day at the start of the century. In 88 centuries, what is the total of the daily increases in time (that is, the sum of the gain on the first day, the gain on the second day, etc.)?
Physics
1 answer:
stira [4]3 years ago
7 0

Answer:

0.088 seconds

0.0880000273785 second

0.08800054757 seconds

Explanation:

In the question it is given each century adds 1 ms to a day due to the slowing rotation of the Earth

In 88 centuries the length of the first day of the year will be

88 × 1 = 88 ms = 0.088 seconds

1 ms = 1 century

1 century = 100 years × 365.25 days

⇒1 ms = 36525 days

1\ day=\frac{1}{365.25}=2.7378\times 10^{-5} ms=2.7378\times 10^{-8} s

Sum of the gain on the first day would be

0.088 + 2.7378×10⁻⁸ = 0.0880000273785 second

Sum of the gain on the second day would be

0.088 + 2.7378×10⁻⁸+2.7378×10⁻⁸ = 0.08800054757 seconds

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3 years ago
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Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h
Dvinal [7]

Answer:

734.16 kg m/s^{2}

Explanation:

The problem is asking for the Force of pushing off the ground.

  • The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

             <em>Acceleration</em>: 12 m/s^{2}

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: \frac{1 kg}{9.80665 N} x \frac{x}{600 N} = \frac{600}{9.80665} = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/s^{2}

F = 734.16 kg m/s^{2}

7 0
3 years ago
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
son4ous [18]

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

\Delta U =U_f - U_i =Q-W

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J

3 0
4 years ago
What is the first step in glycolysis
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Hexokinase is the correct answer
4 0
3 years ago
If a 5.0 kg box is pulled simultaneously by a 10.0 N force and a 5.0 N force, then its acceleration must be Group of answer choi
vivado [14]

Answer:

We cannot tell from the information given

Explanation:

Given;

mass of the box, m = 5 kg

first force, F₁ = 10 N

second force, F₂ = 5 N

(I) Assuming the two forces are acting horizontally in opposite direction, the resultant force on the box is calculated as;

∑Fx = 10 N - 5 N

      = 5 N

Apply Newton's second law of motion;

∑Fx = ma

a = ∑Fx/m

a = 5 / 5

a = 1 m/s² in the direction of the 10 N force.

(II) Also, if the two forces are acting in the same direction, the resultant force is calculated as;

∑Fx = 10 N + 5 N

∑Fx = 15 N

a = 15 / 5

a = 3 m/s²

Therefore, the information given is not enough to determine the acceleration of the box.

8 0
3 years ago
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