2 years ago

Which option is part of designing a set of experimental procedures?

Physics

2 answers:

zloy xaker [14]2 years ago

4 0

B identifying the types of data to be gathered

vesna_86 [32]2 years ago

4 0

The answer is B. Identifying the types of data to be gathered

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you push a book a distance of 5 meters with a force of 10 newtons for 2 seconds how much work did you do on the book

GrogVix [38]

Answer:

50 J

Explanation:

Work, W=Fd where F is the applied force and d is the distance

Substituting 10 N for F and 5 m for d then work done on the book can be expressed as

W=10 N* 5 m=50 Nm= 50 J

Therefore, the work done is equivalent to 50 J

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2 years ago

A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.4 ft/s,

Art [367]

Answer:

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

Explanation:

given,

length of ladder = 10 ft

let x be the distance of the bottom and y be the distance of the top of ladder.

x² + y² = 100

differentiating with respect to time we get

$2 x\dfrac{dx}{dt}+2y\dfrac{dy}{dt} = 0$ ..............(1)

when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s

from equation (1)

now,

$16\times 1.4 + 12\dfrac{dy}{dt} = 0$

$\dfrac{dy}{dt} = -\dfrac{5.6}{3}$

let the angle between the ladders be θ

$tan\theta = \dfrac{y}{x}$

y = xtan θ

$\dfrac{dy}{dt} =\dfrac{dy}{dt} tan\theta + x sec^2\theta\dfrac{d\theta}{dt}$

$-\dfrac{5.6}{3} =1.4\times \dfrac{6}{8} + 8 (1+\dfrac{9}{16})\dfrac{d\theta}{dt}$

$\dfrac{25}{2} \dfrac{d\theta}{dt} =\dfrac{-17.5}{6}$

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

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2 years ago

The universal force that is effective over the longest distance between very massive objects like planets is

fenix001 [56]

The universal force that is effective over the longest distance between very massive objects like planets is Gravity

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3 years ago

If someone is moving at a constant speed of 100 km/h and accelerate to 120km /h in 10 s what is the acceleration

Alex Ar [27]

The acceleration should be a gain of 2 km/h per second

5 0

2 years ago

A 3,000-N force gives an object an acceleration of 15 m/s^2. The mass of the object is

Bingel [31]

<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

According to the second Newton's Law,

m = 3000/15
m = 200 kg

The mass of the object is therefore 200 kg.

7 0

2 years ago

Read 2 more answers