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3 years ago

12

Which option is part of designing a set of experimental procedures?

2 answers:

zloy xaker [14]3 years ago

4 0

B identifying the types of data to be gathered

vesna_86 [32]3 years ago

4 0

The answer is B. Identifying the types of data to be gathered

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Find the intensity of a 55 dB sound given I 0=10^-12W/m^2

MakcuM [25]

Answer:

3.16 × $10^{-7}$ W/ $m^{2}$

Explanation:

β(dB)=10 × $log_{10}(\frac{I}{I_{0} })$

$I_{0}$ = $10^{-12}$ W/ $m^{2}$

β=55 dB

Therefore plugging into the equation the values,

55=10 $log_{10}(\frac{I}{ [tex]10^{-12}$ })[/tex]

5.5= $log_{10}(\frac{I}{ [tex]10^{-12}$ })[/tex]

$10^{5.5}$ = $\frac{I}{10^{-12} }$

316227.76× $10^{-12}$ = I

I= 3.16 × $10^{-7}$ W/ $m^{2}$

5 0

3 years ago

While standing outdoors one evening, you are exposed to the following four types of electromagnetic radiation: yellow light from

Alona [7]

Answer: FM radio waves, AM radio waves, yellow light, micro waves

Explanation:

5 0

3 years ago

Read 2 more answers

Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...

Romashka [77]

Answer:

inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

8 0

2 years ago

Normal atmospheric pressure is 1.013 105 Pa. The approach of a storm causes the height of a mercury barometer to drop by 27.1 mm

Burka [1]

Answer:

The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

Explanation:

Given that,

Atmospheric pressure $P_{atm}= 1.013\times10^{5}\ Pa$

drop height h'= 27.1 mm

Density of mercury $\rho= 13.59 g/cm^3$

We need to calculate the height

Using formula of pressure

$p = \rho g h$

Put the value into the formula

$1.013\times10^{5}=13.59\times10^{3}\times9.8\times h$

$h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}$

$h=0.76\ m$

We need to calculate the new height

$h''=h - h'$

$h''=0.76-27.1\times10^{-3}$

$h''=0.76-0.027$

$h''=0.733\ m$

We need to calculate the atmospheric pressure

Using formula of atmospheric pressure

$P=\rho g h$

Put the value into the formula

$P= 13.59\times10^{3}\times9.8\times0.733$

$P=0.97622\times10^{5}\ Pa$

Hence, The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

7 0

3 years ago

2. A stone is thrown vertically upward with a speed of 22m/s.

Eduardwww [97]

Answer:

Explanation:

Energy E is conserved:

$E=\frac{1}{2}mv^2+mgh$

If v₀ = 22m/s, h₀=0m and h₁=25m:

$E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1$

Solving for v₁:

$v_1=\sqrt{v_0^2-2gh_1}$

There is no real solution, because the stone never reaches 25m.

7 0

3 years ago